The chemical activity series is the arrangement of the elements descendingly according to their chemical activity for reactions like simple substitution reactions and redox reactions. Elements above hydrogen can replace hydrogen from water and acids as they are more active than hydrogen. Since cesium is more active than hydrogen, it replaces it in hydrochloric acid.
2 cesium atoms loses 2 electrons first;
2Cs --> 2Cs+ + 2e-
2 hydrogen atoms recieve the two electrons;
2H+ + 2e- --> H2
The net ionic equation is;
2Cs + 2HCl --> CsCl + H2
<h3>Hi!</h3>
<h3>The correct options would be:</h3>
1, 3 and 4.
In an alpha decay, the atom's mass number is reduced by 4, and the atomic number is reduced by two following the emission of an alpha particle (2 protons and 2 neutrons).
In gamma decay, the atom releases energy spontaneously to stabilize itself, and this energy is released in the form of photons.
<h3>Hope this helps!</h3>
Answer:
This is man made and natural
Answer:
0.924 g
Explanation:
The following data were obtained from the question:
Volume of CO2 at RTP = 0.50 dm³
Mass of CO2 =?
Next, we shall determine the number of mole of CO2 that occupied 0.50 dm³ at RTP (room temperature and pressure). This can be obtained as follow:
1 mole of gas = 24 dm³ at RTP
Thus,
1 mole of CO2 occupies 24 dm³ at RTP.
Therefore, Xmol of CO2 will occupy 0.50 dm³ at RTP i.e
Xmol of CO2 = 0.5 /24
Xmol of CO2 = 0.021 mole
Thus, 0.021 mole of CO2 occupied 0.5 dm³ at RTP.
Finally, we shall determine the mass of CO2 as follow:
Mole of CO2 = 0.021 mole
Molar mass of CO2 = 12 + (2×16) = 13 + 32 = 44 g/mol
Mass of CO2 =?
Mole = mass /Molar mass
0.021 = mass of CO2 /44
Cross multiply
Mass of CO2 = 0.021 × 44
Mass of CO2 = 0.924 g.
Answer:
A centigrade thermometer (Celsius) has 100 divisions or intervals between the normal freezing point and the normal boiling point of water. There are 180 divisions or intervals between the boiling and freezing temperatures when using the Fahrenheit scale. One Kelvin is equal in size to one degree Celsius.
Explanation: