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bezimeni [28]
3 years ago
15

What is a word problem for the equation 5 times n equals 20

Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0
5n=20 is the equation 5 times n equals 20

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Help.It have answer choices​
amm1812
The answer is Impossible
6 0
3 years ago
Read 2 more answers
8 3/4 + 9 5/9= <br> with working?
Gre4nikov [31]

8 3/4 + 9 5/9 Add 8 and 9

17 + 3*9/4*9 + 5*4/9*4 Find common denominator

17 + 27/36 + 20/36 Add

17 + 47/36 Convert into mixed fraction

17 + 1 11/36 Simplify mixed fraction

18 11/36. Answer

If you need the decimal form, it is 18.31. But other than that, the answer is 18 11/36.

4 0
3 years ago
Solve the equation. Write a justification for each step. <br>5m-3=22
balu736 [363]

Answer:

m=5

Step-by-step explanation:

5m-3=22

  1. take 3 the other side by doing the opposite operation

5m= 22+3

5m= 25

  • then divide it by 5 on both sides to get the value of m.
  • 5m÷5=25÷5
  • 5and 5 cancels out and the answer becomes :

m=5

5 0
3 years ago
Read 2 more answers
Is 2 to the power of 3 equal to 3 to the power of 2
Mama L [17]

Answer:

No

Step-by-step explanation:

2^{3}=2•2•2=8

{3}^2=3•3=9

8≠9

4 0
3 years ago
6. Let f and g be differentiable functions
Julli [10]

Answer:

(b) 1

Step-by-step explanation:

To differentiate h(x)=f(x)g(x) we will need the product rule:

h'(x)=f'(x)g(x)+f(x)g'(x).

We have h'(x)=f(x)g'(x), so the following equation is true by the transitive property:

f'(x)g(x)+f(x)g'(x)=f(x)g'(x)

By subtraction property we have:

f'(x)g(x)=0

Since g(x) \neq 0, then we can divide both sides by g(x):

f'(x)=\frac{0}{g(x)}

f'(x)=0

This implies f(x) is constant.

So we have that f(x)=c where c is a real number.

Since f(0)=1 and f(0)=c, then by transitive property 1=c.

So f(x)=1.

Checking:

h(x)=1 \cdot g(x)

h'(x)=g'(x)=1 \cdot g'(x)

So the following conditions were met.

5 0
3 years ago
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