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Eduardwww [97]
3 years ago
13

A 4-kg toy car with a speed of 5 m/s collides head-on with a stationary 1-kg car. After the collision, the cars are locked toget

her with a speed of 4 m/s. How much kinetic energy is lost in the collision?
Physics
1 answer:
mihalych1998 [28]3 years ago
4 0

Kinetic energy lost in collision is 10 J.

<u>Explanation:</u>

Given,

Mass, m_{1} = 4 kg

Speed, v_{1} = 5 m/s

m_{2} = 1 kg

v_{2} = 0

Speed after collision = 4 m/s

Kinetic energy lost, K×E = ?

During collision, momentum is conserved.

Before collision, the kinetic energy is

\frac{1}{2} m1 (v1)^2 + \frac{1}{2} m2(v2)^2

By plugging in the values we get,

KE = \frac{1}{2} * 4 * (5)^2 + \frac{1}{2} * 1 * (0)^2\\\\KE = \frac{1}{2} * 4 * 25 + 0\\\\

K×E = 50 J

Therefore, kinetic energy before collision is 50 J

Kinetic energy after collision:

KE = \frac{1}{2} (4 + 1) * (4)^2 + KE(lost)

KE = 40J + KE(lost)

Since,

Initial Kinetic energy = Final kinetic energy

50 J = 40 J + K×E(lost)

K×E(lost) = 50 J - 40 J

K×E(lost) = 10 J

Therefore, kinetic energy lost in collision is 10 J.

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Answer:

a) 34.05ft/s

b).1156.2BTU/lbm

c) 2.04BTU/s

Explanation:

Amount of liquid that has evaporated, m = ◇Vliq/ Vf

We replace the values to make conversion

m = (0.6gal/ 0.01683ft^3/lbm) × (0.13368ft^3/1gal)

m = 4.755lb

The mass flow rate of exit steam is given by:

m' = m/◇t

We replace values to make conversion

m' =( 4.766lb/45min) = 0.1059lb/min × 1min/60s

m' = 0.001765lb/s

The exit velocity V = m'/pA = m'Vg/A

We replace values to make conversion

V =[ (0.001765lbm/s)(20.093ft^3/lbm) /(0.15 in^2)]× (144in^2/1ft^2)

V = 34.05ft/s

b) The total and flow energies per unit mass is given by:

Eflow= Pv = h - u

We replace the values to make conversion

Eflow = 1156.2 - 1081.8

Eflow = 74.4BTU/lbm

Therefore theta= h + ke + pe

Theta approximately =h = 1156.2BTU/lbs

c) The rate at which energy is leaving the cooler by steam is given by:

Emass = m'theta

Emass = (0.001765)×(1156.2)

Emass = 2.04BTU/s

6 0
3 years ago
To charge an electroscope negatively by induction you need: a) a positively charged rod and a ground b) a negatively charged rod
Zolol [24]

Answer:

Option a)

Explanation:

In the process of charging anything by the method of induction, a charged body is brought near to the body which is neutral or uncharged without any physical contact and the ground must be provided to the uncharged body.

The charge is induced and the nature of the induced charge is opposite to that of the charge present on the charged body.

So when a positively charged rod is used to charge an electroscope, the rod which is positive attracts the negative charge in the electroscope and the grounding of the electroscope ensures the removal of the positive charge and renders the electroscope negatively charged.

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3 years ago
Refer to the diagram to answer the question. Which part of the eye enables it to focus? A B C D E
Ilia_Sergeevich [38]

Answer:

what are the A B C D E

Explanation:

8 0
2 years ago
Steam enters a turbine at 400K and exhausts at 360K. Calculate the maximum efficiency. =%
kozerog [31]

The maximum efficiency is 10%

Explanation:

The maximum efficiency of a machine is given by:

\eta=1-\frac{T_C}{T_H}

where

T_H is the temperature of the hot reservoir

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For the machine in this problem, we have:

T_H=400K is the temperature of the hot reservoir

T_C=360K is the temperature of the cold reservoir

substituting, we find the max efficiency:

\eta=1-\frac{360}{400}=0.1

So, the efficiency is 0.10 (10%).

Learn more about temperature:

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8 0
3 years ago
A total charge of 0.009 passes through a cross sectional area of a nichrome wire in 3.5 s. What is the current in the wire?
Marrrta [24]

Answer:0.003 amperes

Explanation:

Quantity of charge=0.009

Time=3.5seconds

current=quantity of charge ➗ time

Current=0.009 ➗ 3.5

Current=0.003 amperes

5 0
3 years ago
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