Kinetic energy =(1/2) (mass) (speed²)
First object: KE = (1/2) (2 kg) (2m/s)² = 4 joules during the lift.
Second object: KE = (1/2) (4kg) (3 m/s)² = 18 joules during the lift.
The second object has more kinetic energy while it's being lifted
than the first object has while it's being lifted. Once they reach their
final heights and stop, neither object has any kinetic energy.
Answer:
Explanation:
Given
First charge of
is placed at 
Second charge
is placed at 
Electric field is given by

Electric field due to
is away from it


Electric field due to


Net electric field will be vector addition of two


Magnitude of Electric field is


P1V1/T1 = P2V2/T2
(1.6atm)(168cm^3)/(255K) = (1.3atm)V2/(285K)
Final volume = 231cm^3
Answer:
Well a meter stick has increments of a centimeter, and since 1 cm=0.01m he should record it as 4.02m(b)
Explanation:
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