Answer: because of the magnetic
Explanation: If you hold a compass near a wire through which current is flowing, the needle on the compass will be deflected. Since compasses work by pointing along magnetic field lines, this means that there must be a magnetic field near the wire through which the current is flowing.
Answer:
initial velocity=12.31 m/s
Final speed= 16.234 m/s
Explanation:
Given Data
height=5.72 m
distance=13.30 m
To Find
Initial Speed=?
Solution
Use the following equation to determine the time of the stone is falling.
d = vi ×t ½ ×9.8 × t²
Where
d = 5.72m and vi = 0 m/s
so
5.72 = ½× 9.8 ×t²
t = √(5.72 ÷ 4.9)
t=1.08 seconds
To determine the initial horizontal velocity use the following equation.
d = v×t
13.30 = v ×1.08
v = 13.30 ÷ 1.08
v=12.31 m/s
To determine stone’s final vertical velocity use the following equation
vf = vi+9.8×t............vi=0 m/s
vf = 9.8×1.08
vf= 10.584 m/s
To determine stone’s final speed use the following equation
Final speed = √[Horizontal velocity²+Final vertical velocity²]
Final speed = √{(12.31 m/s)²+(10.584 m/s)²}
Final speed= 16.234 m/s
Answer:
The distance that separates the two particles is 7.42 cm.
Explanation:
Given;
the mass of each particle, m = 3 mg = 3 x 10⁻⁶ kg
the magnitude of charge of each particle, q = 6.0 nC
speed of each particle, v = 5.0 m/s
a = v/t
where;
a is the acceleration of the two particles
v is the final velocity
t is time
v = u + gt
5 = 0 + 9.8t
5 = 9.8t
t = 5/9.8
t = 0.51 s
a = v/t
a = 5/0.51 = 9.8 m/s²
Total force on the two particles = (2m)a = (2* 3 x 10⁻⁶)9.8
F = 5.88 x 10⁻⁵ N
Substitute in the value of F in the above equation and calculate r
where;
k is coulomb's constant = 8.99 x 10⁹ Nm²/c²
r is the distance of separation between the two particles
Therefore, the distance that separates the two particles at the instant when each has a speed of 5.0 m/s, is 7.42 cm.
