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Ksenya-84 [330]
4 years ago
12

When you mix two gases what can you predict about the conservation of volume in this case?

Physics
1 answer:
o-na [289]4 years ago
3 0
Amagat's law of additive volumes states that we can simply add up the individual volumes of each gas (provided they are at the same temperature and pressure) to get the total volume of the mixture. Conservation of volume is an acceptable assumption for gases (but not always for liquid mixtures). This works for gases since the molecules are very small and only take up a minimal amount of space in a gas.
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Why do compass needles around a current carrying wire point in different directions
Marizza181 [45]

Answer: because of the magnetic

Explanation:  If you hold a compass near a wire through which current is flowing, the needle on the compass will be deflected. Since compasses work by pointing along magnetic field lines, this means that there must be a magnetic field near the wire through which the current is flowing.

3 0
3 years ago
A stone thrown horizontally from a height of 5.72 m hits the ground at a distance of 13.30 m. Calculate the initial speed of the
kakasveta [241]

Answer:

initial velocity=12.31 m/s

Final speed= 16.234 m/s

Explanation:

Given Data

height=5.72 m

distance=13.30 m

To Find

Initial Speed=?

Solution

Use the following equation to determine the time of the stone is falling.  

d = vi ×t   ½ ×9.8 × t²

Where  

d = 5.72m and vi = 0 m/s

so  

5.72 = ½× 9.8 ×t²

t = √(5.72 ÷ 4.9)

t=1.08 seconds

To determine the initial horizontal velocity use the following equation.

d = v×t

13.30 = v ×1.08

v = 13.30 ÷ 1.08

v=12.31 m/s

To determine stone’s final vertical velocity use the following equation

vf = vi+9.8×t............vi=0 m/s

vf = 9.8×1.08

vf= 10.584 m/s

To determine stone’s final speed use the following equation  

Final speed = √[Horizontal velocity²+Final vertical velocity²]

Final speed = √{(12.31 m/s)²+(10.584 m/s)²}

Final speed= 16.234 m/s

3 0
4 years ago
Please help soon!!!!
anyanavicka [17]
The Answer: Parallel
6 0
4 years ago
Read 2 more answers
If i ask wat r the application of simple machine some of u will say-----> Simple machines that are widely used include the wh
TiliK225 [7]

Answer:

DID NOT

UNDER STAND

Explan it a littlebit

3 0
3 years ago
Two particles, each having a mass of 3.0 mg and having equal but opposite charges of magnitude of 6.0 nC, are released simultane
algol13

Answer:

The distance that separates the two particles is 7.42 cm.

Explanation:

Given;

the mass of each particle, m = 3 mg = 3 x 10⁻⁶ kg

the magnitude of charge of each particle, q = 6.0 nC

speed of each particle, v = 5.0 m/s

F = ma = \frac{kq^2}{r^2}

a = v/t

where;

a is the acceleration of the two particles

v is the final velocity

t is time

v = u + gt

5 = 0 + 9.8t

5 = 9.8t

t = 5/9.8

t = 0.51 s

a = v/t

a = 5/0.51 = 9.8 m/s²

Total force on the two particles = (2m)a = (2* 3 x 10⁻⁶)9.8

F = 5.88 x 10⁻⁵ N

Substitute in the value of F in the above equation and calculate r

F = \frac{kq^2}{r^2}

where;

k is coulomb's constant = 8.99 x 10⁹ Nm²/c²

r is the distance of separation between the two particles

F = \frac{kq^2}{r^2} \\\\r^2 = \frac{kq^2}{F}\\\\r = \sqrt{ \frac{kq^2}{F}} = \sqrt{ \frac{8.99*10^9*(6*10^{-9})^2}{5.88*10^{-5}}} = 0.0742 \ m

Therefore, the distance that separates the two particles at the instant when each has a speed of 5.0 m/s, is 7.42 cm.

7 0
3 years ago
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