Answer: A projectile is any object in which the only force is gravity
Explanation: Equations on how to calculate projectile velocity is stated below:
The initial velocity Vo being a vector quantity, has two componentsVox and Voy  
V0x = V0 cos(θ) 
V0y = V0 sin(θ) 
The acceleration A is a also a vector with two components Axand Ay given
Ax = 0 and Ay = - g = - 9.8 m/s2 
Along the x axis the acceleration is equal to 0 and therefore the velocity Vx is constant  
Vx = Vocos(θ) 
Along the y axis, the acceleration is uniform and equal to - g and the velocity at time t is g
Vy = Vo sin(θ) - g t 
Along the x axis the velocity Vx is constant and therefore the component x of the displacement is
x = Vocos(θ) t 
Along the y axis, the motion is of uniform acceleration and the y component of the displacement is
y = Vo sin(θ) t - (1/2) g t2 
 
        
             
        
        
        
Answer:
14,700 N
Explanation:
The hyppo is standing completely submerged on the bottom of the lake. Since it is still, it means that the net force acting on it is zero: so, the weight of the hyppo (W), pushing downward, is balanced by the upward normal force, N:
 (1)
 (1)
the weight of the hyppo is

where m is the hyppo's mass and g is the gravitational acceleration; therefore, solving eq.(1) for N, we find

 
        
             
        
        
        
Answer:
spring compressed is 0.724 m 
Explanation:
given data 
mass = 1.80 kg
spring constant k = 2 × 10²  N/m
initial height = 2.25 m
solution
we know from conservation of energy is 
mg(h+x)  = 0.5 × k × x²       ...................1
here x is compression in spring 
so put here value in equation 1 we get 
1.8 × 9.8 × (2.25+x)  = 0.5 × 2× 10² × x² 
solve it we get 
x = 0.724344
so spring compressed is 0.724 m 
 
        
             
        
        
        
Answer:
The number of atoms is 
Explanation:
From the question we are told that 
                  The mass of coin  is 
                    Number of atom in one mole = 
                    Molar mass of nickel 
Now the relation to obtain the number of atom in  the  nickel coin is 
                         
                            
                            