Calculate the change in heat of the aluminum; show all calculations. Calculate the change in heat of the water; show all calcula
tions. Are the two values the same? Why or why not? See the attached picture for the numbers.
I got -3443.14 J for the aluminum and 3443.595 for the water
I got -3443.14 J for the aluminum and 3443.595 for the water
1 answer:
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Answer:
Given:
Radius of ball bearing (r) = 1.5 mm = 0.15 cm
Density of iron (ρ) = 7.85 g/cm³
Density of glycerine (σ) = 1.25 g/cm³
Terminal velocity (v) = 2.25 cm/s
Acceleration due to gravity (g) = 980.6 cm/s²
To Find:
Viscosity of glycerine ()
Explanation:
Substituting values of r, ρ, σ, v & g in the equation:
Answer
given,
mass of ball = 5.93 kg
length of the string = 2.35 m
revolve with velocity of 4.75 m/s
acceleration due to gravity = 9.81 m/s²
T cos θ = mg
T cos θ =
T cos θ = 58.17
T² - 56.93T - 3383.75 = 0
T = 93.22 N
θ = 51.39°
The period will be the same if the amplitude of the motion is increased to 2a
What is an Amplitude?
Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.
Here,
mass m is attached to the spring.
mass attached = m
time period = t
We know that,
The time period for the spring is calculated with the equation:
Where k is the spring constant
Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.
From the equation, we can say,
Time period of the spring is independent of the amplitude.
Hence,
Increasing the amplitude does not affect the period of the mass and spring system.
Learn more about time period here:
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