9514 1404 393
Answer:
5/3
Step-by-step explanation:
The prime factorizations are ...
10 = 2·5
12 = 2·2·3
Then *10* = 5 and *12* = 3, so *10*/*12* = 5/3.
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
Answer:find the solution to the system of equations below.start by adding the equation
{-2x+2y=-8
{2x+y=5
Step-by-step explanation:The given system of equation are:
1---- y= x -4
2----- y=4 x+2
Equation (1) - Equation (2)
→0= x -4 - (4 x+2)
→0= -3 x -6-----[Adding and subtracting like terms]
Adding 3 x on both sides
→3 x= -6
Dividing by 3 on both sides
→x = -2
→Substituting the value of x in equation 1, we get
y= -2 -4
y =-6
→Solution set =(x,y)=(-2, -6)
Don't used the graph to find the solution.
Answer:
X= 9/2
Alternative form
x=4 1/2, x=4.5
Step-by-step explanation:
*= Multiply
1. log (little 10 under) (2)*(3x-1)= log (little 10 under) (2)*(x+8)
2. then divide both side by log (little 10 under (2))
3. 3x-1=x+8
4. move variable to the left side and change its sign
5. 3x-x-1=8
6. then move constant to the right side and change its sign
7. 3x-x=8+1
8. collect like terms
9. 2x=8+1
10. add 8+1
11. 2x=9
12. then divide both sides by 2
13. 2/2 9/2
14. 2/2 cancels out so x=9/2 is the answer
9514 1404 393
Answer:
d = kw/p
Step-by-step explanation:
When d varies directly with w, the equation is ...
d = kw
When d varies inversely with p, the equation is ...
d = k/p
When d does both, the equation is ...
d = kw/p