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ArbitrLikvidat [17]
3 years ago
11

H-H + CI-CI → H-CI+H-CI

Chemistry
1 answer:
Jet001 [13]3 years ago
8 0

Answer:

if this is balanced or unbalanced equations then this one is balanced since there is 2 H on each side and 2 Cl's on each side  

Explanation:

You might be interested in
A sample that is 74.5 percent chloride by mass is dissolved in water and treated with an excess of
12345 [234]

Answer:

Total mass of original sample = 0.38 g

Explanation:

Percentage of chloride = 74.5%

Mass of AgCl  precipitate = 1.115 g

Mass of original sample = ?

Solution:

Mass of chloride:

1.115 g/ 143.3 g/mol × 35.5 g/mol

0.0078 g × 35.5 = 0.28 g

Total mass of compound:

Total mass = mass of chloride / %of Cl × 100%

Total mass = 0.28 g/ 74.5% × 100%

Total mass = 0.0038 g× 100

Total mass = 0.38 g

5 0
4 years ago
Use the data provided to calculate benzaldehyde's heat of vaporization smartwork5
QveST [7]
This problem is incomplete. Luckily, I found a similar problem from another website shown in the attached picture. The data given can be made to use through the Clausius-Clapeyron equation:

ln(P₂/P₁) = (-ΔHvap/R)(1/T₂ - 1/T₁)

where
P₁ = 14 Torr * 101325 Pa/760 torr = 1866.51 Pa
T₁ = 345 K
P₂ = 567 Torr * 101325 Pa/760 torr = 75593.78 Pa
T₂ = 441 K

ln(75593.78 Pa/1866.51 Pa) = (-ΔHvap/8.314 J/mol·K)(1/441 K - 1/345 K)
Solving for ΔHvap,
<em>ΔHvap = 48769.82 Pa/mol or 48.77 kPa/mol</em>

6 0
3 years ago
There’s a part two for this but I can’t fit it all in this image, if you know how to do this please help me out. I’m stuck on th
Alina [70]

Answer:

See explanation

Explanation:

According to the law of conservation of mass; the total mass of reactants on the left hand side of the reaction equation is equal to the total mass of products on the right hand side of the reaction equation.

Hence, the total mass of each atom on either side of the reaction equation should be exactly the same.

Since there are two atoms of oxygen on the reactants side, the total mass of oxygen = 16 amu * 2 = 32 amu

Since there are two oxygen atoms on the products side, total mass of oxygen = 16 amu * 2 = 32 amu

8 0
3 years ago
What is the ratio (in the form of a decimal) of the root-mean-square speed of 238UF6 to that of 235UF6 at constant temperature?
NNADVOKAT [17]

Answer:

ratio=0.996m/s

Explanation:

RMS=\sqrt{\frac{3RT}{M} }; M= molecular weight of compound;

RMS speed is inversly proportional to the molecular weight hence compound having less molecular weight will have more rms speed value.

V1 for 238 UF_{6}; M1=238+114=352g/mole

V1 for 235 UF_{6}; M1=238+114=352g/mole

V1=\sqrt{\frac{3RT}{352} };

V2=\sqrt{\frac{3RT}{349} };

\frac{V1}{V2}=ratio of 238UF_{6} F6 to 235UF_{6}=\sqrt{\frac{349}{352} };

\frac{V1}{V2} =0.9957m/s;

\frac{V1}{V2} =0.996m/s;

4 0
3 years ago
For an aqueous solution of sodium chloride (NaCl) .Determine the molarity of 3.45L of a solution that contains 145g of sodium
worty [1.4K]
Molar mass NaCl = 58.44 g/mol

number of moles:

mass NaCl / molar mass

145 / 58.44 => 2.4811 moles of NaCl

Volume = 3.45 L

Therefore :

M = moles / volume in liters:

M = 2.4811 / 3.45

M = 0.719 mol/L⁻¹

hope this helps!
6 0
4 years ago
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