Question

On a day wilderness expedition you'll need to heat of water to the boiling point each day. The air temperature will average . You have available canisters of compressed propane fuel, which you'll burn to heat the water. Each canister has of propane in it. What is the minimum number of fuel canisters you must bring? The standard heat of formation of propane at is . You'll probably find other helpful data in the ALEKS Data resource.

Answer 1

Answer:

Hi, this question lacks necessary values. Certain values are needed for it be answered  

Explanation:

https://www.bartleby.com/questions-and-answers/on-a-5-day-wilderness-expedition-youll-need-to-heat-4.0kg-of-water-to-the-boiling-point-each-day.-th/6f3e7e8a-1c4e-4ecc-a6ca-380a5b1482d5

I will use some certain values found using the above link to solve this question.

Lets assume that

specific heat capacity of water (c) = 4.18 Jg-1k-1

Mass of water (M) = 4kg =4000g

initial temperature of water = 25oC

mass of propane (C3H8) in each canister = 75g

standard heat of combustion of propane =-103.85 KJ mol-1

Step 1: Calculate the heat gained by water (Q)

          Q= M x C x ΔT

           Q = 4000 x 4.18 x (100-25)

           Q = 1,250,000 joules

           Q = 1250 KJ

           Q = 1250 KJ is needed in a day wilderness expedition

Step 2: Calculating how many fuel canisters that are used

The standard heat of combustion of propane  is -103.85 KJ mol-1. This means that 103.85 of heat is released when 1 mole of propane is completely burnt. So 1250 KJ of heat will be released by x moles of propane

             x = 1250 / 103.85

             x = 12.04 moles

Then, calculate the mass of propane  (The molar mass of propane = 44 g/mol)

             Mole = mass / molar mass

             mass = mole x molar mass

             mass = 12.04 x 44

             mass = 529.76 g

A canister contains 75 g

The number of canister needed will be = 529.76 / 75

                                                                 = 7.06 canisters

                                                                 = 7 canisters approximately

Answer 2

Answer:

36

Your question is not complere. but maybe it is like:

5 day expedition.

you'll need to heat 4.0kg

Air Temperature: 25 °C

each canister has 75 g

The standar heat of formation of propane at 25°C is −103.85 / kJmol...

If the data is not exactly the same, you can follow the same steps.

Explanation:

Given:

Weight of water = 4.0 kg = 4000 g

Boiling point  = 100 °C (T2)

Initial T ° Water= 25 °C (T1)

Specific heat capacity water (Cs) = 4.184 J / g°C

Then  

Energy (q) = m x Cs x (T2-T1)

q = 4000 g x  4.184 J / g°C x (100-25) °C

q = 1255200 J per day

For 5 days the amount of energy will be 5xq = 6276000 J = 6276 kJ

Then we know that the standard heat of formation of propane at 25°C is −103.85kJ/mol. Also, Molecular Weight propane= 44,1 g / mol

 

Then we can know how much propane it's needed:

Mass= 6276 kJ÷103.85 kJ / mol = 60.43 mol

Mass of propane= 60.43 mol ×  44,1 g/mol = 2664.9 g  

So, if each canister has 75.g of propane:  

Number of canister=  2664.9 g ÷ 75.g = 35.53 = 36 canisters