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Anastaziya [24]
2 years ago
9

I need to know “ The carbon atom that has the chlorine atone has an optical activity “

Chemistry
1 answer:
katrin2010 [14]2 years ago
3 0

Answer: R

Explanation: is polarized to the right

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In a neutral atom they are both equal, and their even quantities makes the atom neutral...
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3 years ago
what is the total displacement of a dog that runs north 80 meters to chase a ball, returns to its master, and runs south 20 mete
vladimir1956 [14]
The total displacement will be 20 meters.
7 0
3 years ago
Think about the lab procedure you just read. Label each factor below with V for “variable” or C for “constant”.
luda_lava [24]
<h2>Answer:</h2><h3>The temperature of the gas: V</h3>

The temperature of gas is a variable quantity. It can be changed by changing energy or pressure of gas.

<h3>The amount of gas in the tube (in terms of mass and moles): C</h3>

It is a constant entity. As mass of gas once taken can not be changed by changing temperature, pressure etc.

<h3>The radius of the tube: C</h3>

The radius of tube cannot change at any rate.

<h3>The temperature of the gas (changed by the water surrounding it):  V</h3>

It can be changed by changing the temperature of water surrounding it.

<h3>The type of gas: C</h3>

It can never be changed.

<h3>The pressure of the gas: V</h3>

It can be changed by simply changing temperature and volume of gas.

8 0
3 years ago
Read 2 more answers
An acid solution is 0.100 M in HCl and 0.210 M in H2SO4. What volume of a 0.150 M solution of KOH must be added to 500.0 mL of t
Dmitry_Shevchenko [17]

Answer:

When we add 0.33L of KOH only the HCl solution will be neutralized. When we add <u>1.4 L</u> of KOH, all of the acid (the HCl and H2SO4 solution) will be neutralized.

Explanation:

<u>Step 1:</u> Data given

The solution has 0.100 M HCl and 0.210 M H2SO4

Molarity KOH = 0.150 M

Volume of acid solution = 500 mL = 0.5 L

<u>Step 2: </u>Calculate moles of HCl

Moles HCl = Molarity HCl * volume

Moles HCl = 0.100 M * 0.5 L

Moles HCl = 0.05 moles

<u>Step 3:</u> Calculate moles of H2SO4

Moles H2SO4 = 0.210 M * 0.5 L

Moles H2SO4 = 0.105 moles

<u>Step 4:</u> The balanced neutralization reaction of KOH with HCl can be written as:

KOH + HCl → KCl + H2O

The mole ratio is 1:1

This means to neutralize 0.05 moles HCl, we need 0.05 moles KOH

<u>Step 5:</u> The balanced neutralization reaction of KOH with H2SO4 can be written as:

2KOH + H2SO4 → K2SO4 + 2H2O

The mole ratio KOH: H2SO4 is 2:1

This means to neutralize 0.105 moles H2SO4 we need 0.210 moles KOH

<u>Step 6: </u>Calculate volume of KOH needed to neutralize the solution

To neutralize the HCl solution: 0.05 moles / 0.150 M = 0.33 L KOH needed

To neutralize the H2SO4 solution: 0.210 moles / 0.150 M = 1.4 L KOH needed

When we add 0.33L of KOH the HCl solution will be neutralized. When we add 1.4 L of KOH the HCl and H2SO4 solution will be neutralized.

4 0
2 years ago
A 258-ml sample of mek, an industrial solvent, is found to have a mass of 0.599 g at and 100c. what is the molar mass of mek?
SVETLANKA909090 [29]
<span>Correct answer is : 72.0 g/mole If we assume Ideal Gas Law, PV = nRT. n = PV/RT = ((0.988 atm)*(0.258 L))/((0.0821 L*atm/mole*K)*(100 + 273.15)) = 0.00832 moles Molar mass = 0.599 g/0.00832 moles = 72.0 g/mole; your answer is E.</span>
4 0
3 years ago
Read 2 more answers
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