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dolphi86 [110]
3 years ago
10

All group I metals react with H2O to a form a metal hydroxide and hydrogen gas. Which of these will react the fastest? A) Li B)

Na C) K D) Cs
plzz help
Chemistry
2 answers:
kifflom [539]3 years ago
8 0

Cesium is the most reactive

kompoz [17]3 years ago
8 0
What group 1 metal reacts the fastest with H2O to form a metal hydroxide and hydrogen gas? Group 1 elements are lithium, sodium, potassium, rubidium and cesium ( or caesium ). The further down the table, the more reactive they are towards water.
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What I know about the Alveoli and Gas exchange
Reptile [31]

Explanation:

What happens during gas exchange in the alveoli?

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What is the role of alveoli in gas exchange?

The alveoli are where the lungs and the blood exchange oxygen and carbon dioxide during the process of breathing in and breathing out. Oxygen breathed in from the air passes through the alveoli and into the blood and travels to the tissues throughout the body.

7 0
2 years ago
Frank wants to make a simple electromagnet. Which of these does Frank need to have to create the electromagnet? A. iron filings
Helga [31]
C
He needs an battery to make the simple electromagnet
6 0
3 years ago
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During photosynthesis, what gas do plants release
ELEN [110]
During photosynthesis, what gas do plants release - oxygen
5 0
2 years ago
The standard enthalpy of formation for glucose [c6h12o6(s)] is −1273.3 kj/mol. what is the correct formation equation correspond
balu736 [363]
The standard formation equation for glucose C6H12O6(s) that corresponds to the standard enthalpy of formation or enthalpy change ΔH°f = -1273.3 kJ/mol is 
     C(s) + H2(g) + O2(g) → C6H12O6(s)
and the balanced chemical equation is 
     6C(s) + 6H2(g) + 3O2(g) → C6H12O6(s)

Using the equation for the standard enthalpy change of formation 
     ΔHoreaction = ∑ΔHof(products)−∑ΔHof(Reactants)
     ΔHoreaction = ΔHfo[C6H12O6(s)] - {ΔHfo[C(s, graphite) + ΔHfo[H2(g)] + ΔHfo[O2(g)]}

C(s), H2(g), and O2(g) each have a standard enthalpy of formation equal to 0 since they are in their most stable forms:
     ΔHoreaction = [1*-1273.3] - [(6*0) + (6*0) + (3*0)]
                           = -1273.3 - (0 + 0 + 0)
                           = -1273.3
8 0
3 years ago
Why is the answer C for this problem?
pshichka [43]

Answer:

\boxed{\text{(C) X}$_{3}$P$_{2}}

Explanation:

Step 1. Identify the Group that contains X

We look at the consecutive ionization energies and hunt for a big jump between them

\begin{array}{crc}n & IE_{n} & IE_{n} - IE_{n-1}\\1 & 730 & \\2 & 1450 & 720\\3 & 7700 & 6250\\4 & 10500 & 2800\\\end{array}

We see a big jump between n = 2 and n = 3. This indicates that X has two valence electrons.

We can easily remove two electrons, but the third electron requires much more energy. That electron must be in the stable, filled, inner core.

So, X is in Group 2 and P is in Group 15.

Step 2. Identify the Compound

X can lose two valence electrons to reach a stable octet, and P can do the same by gaining three electrons.

We must have 3 X atoms for every 2 P atoms.

The formula of the compound is \boxed{\text{X}$_{3}$P$_{2}}$}.

4 0
3 years ago
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