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ioda
3 years ago
8

In the 1 H NMR spectrum of chloroethane the methylene group is split into a quartet by the α and β nuclear spins of the protons

on the neighboring methyl group. If the external magnetic field, Bo, directs upward, which sequence of nuclear spins contributes to the second farthest peak downfield within the spin-spin splitting pattern?
Chemistry
1 answer:
erastova [34]3 years ago
7 0

Answer:+1/2 and -1/2.

Explanation:the presence of an external magnetic field (B0), two spin states exist, +1/2 and -1/2.

The magnetic moment of the lower energy +1/2 state is aligned with the external field, but that of the higher energy -1/2 spin state is opposed to the external field.

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Un mol de Neón ocupa un volumen de 5 lt y una temperatura 300°K, cuál será su volumen si la temperatura disminuye en 50 °K, P y
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Answer:

No hoblo englas

Explanation:

7 0
2 years ago
uranium-232 has a half-life of 68.8 years. after 344.0 years how much uranium-232 will remain from a 125.0g sample
GaryK [48]

Answer:

4 grams

Explanation:

A = A₀e^⁻kt

A₀ = 125.0 grams

k= 0.693/t(1/2) = (0.693/68.8) yrs⁻¹ = 0.01 yrs⁻¹

t = 344.0 years

A = 125.0g·[e^-(0.01yrs⁻¹)(344.0yrs)] = 125(0.032)grams = 4.000g (4 sog. figs. based on A₀ = 125.0 grams)

4 0
3 years ago
Read 2 more answers
How many molecules of oxygen are produced when a sample of 38.9 g of water is decomposed by electricity?
statuscvo [17]

Answer:

A) 6.5\times 10^{23}\ \text{molecules}

Explanation:

m = Mass of water = 38.9

M = Molar mass of water = 18 g/mol

N_A = Avogadro's number = 6.022\times 10^{23}\ \text{mol}^{-1}

The reaction of electrolysis would be

2H_2O(l)\rightarrow 2H_2(g)+O_2(g)

Number of moles of H_2O

n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{38.9}{18}\ \text{mol}

From the reaction it can be seen that 2 moles of H_2O gives 1 mole of O_2

So, number of moles of O_2 produced is

\dfrac{38.9}{18}\times \dfrac{1}{2}=1.081\ \text{mol}

Number of molecules

1.081N_A=1.081\times 6.022\times 10^{23}\\ =6.5\times 10^{23}

So, 6.5\times 10^{23}\ \text{molecules} of oxygen is produced.

8 0
2 years ago
What is the partial pressure of argon, par, in the flask? express your answer to three significant figures and include the appro
monitta
Given which are missing in your question:
the flask is filled with 1.45 g of argon at 25 C° 
So according to this formula (Partial pressure):
PV= nRT
first, we need n, and we can get by substitution by:
n =  1.45/mass weight of argon
   = 1.45 / 39.948 = 0.0363 mol of Ar
we have R constant = 0.0821
and T in kelvin = 25 + 273 = 298
and V = 1 L
∴ P * 1 = 0.0363* 0.0821 * 298 = 0.888 atm

3 0
3 years ago
Which half-reaction correctly represents reduction?
Gemiola [76]
Answer choice C. Reduction has its electrons as a reactant.
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3 years ago
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