Answer:
2PO₄³⁻ + 3Fe²⁺ → Fe₃(PO₄)₂(s)
Explanation:
In a net ionic equation you list <em>only the ions that are participating in the reaction. </em>
When potassium phosphate, K₃PO₄, reacts with iron (II) nitrate, Fe(NO₃)₂ producing iron (II) phosphate, Fe₃(PO₄)₂ that is an insoluble salt. The reaction is:
2K₃PO₄ + 3 Fe(NO₃)₂ → Fe₃(PO₄)₂(s) + 6NO₃⁻ + 6K⁺
The ionic equation is:
6K⁺ + 2PO₄³⁻ + 3Fe²⁺ + 6NO₃⁻→ Fe₃(PO₄)₂(s) + 6NO₃⁻ + 6K⁺
Subtracting the K⁺ and NO₃⁻ ions that are not participating in the reaction, the net ionic equation is:
<h3>2PO₄³⁻ + 3Fe²⁺ → Fe₃(PO₄)₂(s)</h3>
<u>Answer:</u> For the given amount of sweat lost, the amount of energy required will be 692,899 Joules.
<u>Explanation:</u>
We are given:
Heat of vaporization for water = 2257 J/g
Amount of sweat lost = 307 grams
Applying unitary method:
For 1 g of sweat lost, the energy required is 2257 Joules
So, for 307 grams of sweat lost, the energy required will be = 
Hence, for the given amount of sweat lost, the amount of energy required will be 692,899 Joules.