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2 years ago

Depicted below you will see the molecules COH2 and SO3 . Why is COH2 polar while SO3 isn’t?

Chemistry

1 answer:

tia_tia [17]2 years ago

7 0

Answer:

See explanation

Explanation:

When we look at SO3 we will notice that the compound is trigonal planar and it is symmetric. This means that it has equal charge distribution hence its dipoles cancel out resulting in a zero net dipole moment.

However, COH2 is also trigonal planar but is non-symmetric. Hence, its dipole moments do not cancel out, hence the molecule has a resultant dipole moment and is a polar molecule

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I need someone to answer these.

SCORPION-xisa [38]

Answer:

The identity of an atom is determined my the number of protons. This is the atomic number.

The particle(s) found inside the nucleus are called protons and neutrons. Their combined mass is referred to as the mass number.

Isotopes have the same number of protons, but different number of neutrons.

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3 years ago

What component of amino acid structure varies among different amino acids?

givi [52]

Answer

The components of the r group of amino acid structure varies among different amino acids

Explanation

As the functional group for amino acids is as:

R-CH-COOH

NH2

only R differs so amino acids also differs. If R is “H” then amino acid is glycine and if R is “CH3” then amino acid is alanine. Hence, R is different for different amino acids. Other components as alpha carbon ( C ), carboxyl group ( COOH ) and amino group ( NH2 ) is fixed for every amino acid.

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2 years ago

What information is given in the MSDS for acetic acid?

Andreyy89

Answer: The reactivity of acetic acid with various chemicals (A)

Explanation: engenuity 2021

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2 years ago

Calculate the solubility (in g/L) of CaSO4(s) in 0.500 M Na2SO4(aq) at 25°C . The sp of CaSO4 is 4.93×10^−5 .

jeka94

When you calculate the first two numbers in 493×10

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3 years ago

copper forms two oxides. On heating 1 g of each in hydrogen 0.888 g and 0.798 g of the metal was obtained. Show that the results

Mashutka [201]

Answer:

For the first oxide, 1 g gives 0.888 g of copper.

Dividing by 0.888 tells us that 1.126 g gives 1 g of copper so has 0.126 g of oxygen.

For the second oxide, 1 g gives 0.798 g of copper.

Dividing by 0.798 tells us that 1.253 g gives 1 g of copper so has 0.253 g of oxygen.

So 1 g of copper combines with either 0.126 g or 0.253 g of oxygen.

Within the limits of experimental error, 0.253 is twice 0.126, confirming the law of multiple proportion.

6 0

2 years ago

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