Speed of Ferry is towards North with magnitude 6.2 m/s
Here if we assume that North direction is along Y axis and East is along X axis then we can say

Now a person walk on ferry with speed 1.5 m/s towards east with respect to Ferry
so it is given as

also by the concept of relative motion we know that

now plug in all values in it


now if we need to find the speed of the person then we need to find its magnitude
so it is given as


When light passes through one transparent medium to another transperent medium it bends and that beding of light is know as refraction of light !
Answer:
P = 3.5 D
Explanation:
As we know that convex lens is to be used to make the near point of eye to be correct
So we will have

here we have


now plug in all values into the formula


now for power of lens


so the power in dioptre is
P = 3.5 D
Answer:
the watt is the unit of power or radiant flax