Answer:
A) v₁ = 5.66 [m/s]
Explanation:
To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conservation before and after a collision.
The linear momentum is equal to the mass by the product of the Velocity.
P = m*v
where:
P = lineal momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
Now, to the right side of the equal sign will take the linear momentum before the collision and to the left side of the equal sign as after the collision.
Pbefore = Pafter
(m₁*v₁) - (m₂*v₂) = (m₁*v₃) + (m₂*v₄)
where:
m₁ = mass of the car = 1450 [kg]
v₁ = velocity of the car before the collision [m/s]
m₂ = mass of the shopping cart = 60 [kg]
v₂ = velocity of the shopping cart before the collision = -1.2 [m/s]
v₃ = velocity of the car after the collision = 5.13 [m/s]
v₄ = velocity of the shopping cart after the collision = 11.75 [m/s]
Now replacing:
(1450*v₁) - (60*1.2) = (1450*5.13) + (60*11.75)
1450*v₁ - 72 = 7438.5 + 705
1450*v₁ = 7438.5 + 705 + 72
1450*v₁ = 8215.5
v₁ = 5.66 [m/s]
