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krek1111 [17]
3 years ago
14

2. A book with a mass of 2 Kg is resting on a shelf 1.5 m off the floor. How much gravitational

Physics
2 answers:
jeka943 years ago
6 0

i hope this helps.......

kobusy [5.1K]3 years ago
4 0

Answer:

Book of mass 2 kg is lifted from floor to the table. The height between floor and the table is 1.5 m. Calculate the work done by gravitational force.

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How much energy or stopping power is needed to bring a car to a stop from 100 mph?
Fed [463]
I think 100 mph pushing the car the opposite direction
3 0
3 years ago
In Trial III, a different, looser, spring is used; its force constant is 23.1 N/m. The suspended mass is the same as the one in
cricket20 [7]

Answer:

T=0.827s

Explanation:

The period of a spring can be calculated with the equation

T=2\pi w

But we know as well that w is given by,

w=\sqrt{\frac{k}{m}}

Replacing,

w=\frac{2\pi}{T}= \sqrt{\frac{k}{m}}\\T=2\pi\sqrt{\frac{k}{m}}\\T=2\pi\sqrt{\frac{0.4}{23.1}}

So we have that

T=0.827s

7 0
3 years ago
A proton is initially moving west at a speed of 1.10 106 m/s in a uniform magnetic field of magnitude 0.281 T directed verticall
kifflom [539]

Answer:

so here it will move in circle with radius 4.06 cm

Explanation:

As we know that proton is moving towards west while the magnetic field is vertically upwards

So here the force on the proton must be perpendicular to the velocity

So here we have

F = q(\vec v \times \vec B)

so here we have

F = qvB sin90

since force is perpendicular to the velocity so here it must be centripetal force

here we have

\frac{mv^2}{R} = qvB

so we have

R = \frac{mv}{qB}

R = \frac{(1.66 \times 10^{-27})(1.10 \times 10^6)}{(1.6 \times 10^{-19})(0.281)}

R = 4.06 cm

so here it will move in circle with radius 4.06 cm

8 0
3 years ago
Liquid pressure is directly proportional to the 1. Volume 2. Mass 3. Density 4. Temperature​
ValentinkaMS [17]

Answer:

density☺️☺️☺️

7 0
3 years ago
The diameter of an atom is about 1 angstrom (10-10 m). In order to develop some intuition for the molecular scale of a gas, assu
pochemuha

Answer:

A) 2.5 * 10^22 molecules

B) 3.33 * 10^-9 m

C) 1134 miles/hour

D) average spacing = 2.1 m ,  New mass = 17 kg

Explanation:

Given data :

diameter of atom = 10^-10 m

volume of air = 1 liter

molar masses : 28 g/mol of N2,  32 g/mol of O2

atmospheric pressure = 10^5 Pa

attached below is the detailed solution

5 0
3 years ago
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