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sineoko [7]
3 years ago
15

You choose a card at random from a standard deck of cards. What is the probability that you do not choose a red 8?

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

Answer:

Step-by-step explanation:

no

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PLEASE HELP< YOU WILL RECEIVE BRAINLIEST AND 50 POINTS!PLEASE DO NOT ANSWER THIS IF YOU DO NOT KNOW IT!
Anton [14]

Answer:

Second one. All data matches

Step-by-step explanation:

Hope it helps:)

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What is the formula for calculating a residual value
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The formula to figure residual value follows: Residual Value = The percent of the cost you are able to recover from the sale of an item x The original cost of the item. For example, if you purchased a $1,000 item and you were able to recover 10% of its cost when you sold it the residual value is $100!!
7 0
2 years ago
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in the previous question, what is the distance from a side of the triangle to the incenter? can someone also explain how to get
denis23 [38]
In centre is the centre of a circle that is inscribed in a triangle, called the incircle, i.e. circle is tangent to all three sides AND located inside the triangle.  An incircle is roughly sketched in the accompanying diagram.

Since all radii of an incircle are equal, we have
4x-1=6x-5
Solving for x,
6x-4x=5-1
x=2
consequently, distance from incentre to each side of the triangle is
4(2)-1=7
check 6x-5=6(2)-5=7... checks.

Answers:
The value of x = 2
The distance from incentre to side of triangle is 7
5 0
3 years ago
39+5h+4g-2h i have been trying 2 work this out 4 ages so plz help
SIZIF [17.4K]
Unless you're given the value of the variables, you can't really solve for anything. The only thing you can do is simplify. 

<span>39+5h+4g-2h
The only like terms are 5h and -2h.

39 + 3h + 4g
This would be the simplified version.</span>
7 0
3 years ago
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Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

Where the terms in f prime f^{1}(a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

f^{1}(a)=f^{1}(-4)=-8/(-4)^{2}

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+f^{1}(-4)(x+4)/1!+  f^{11}(-4)(x+4)^{2}/2!.............

=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+  24/(-4)^{3} (-4)(x+4)^{2}/2!.............

=-2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

3 0
1 year ago
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