I will give brainlest f(−5)=?

alukav5142 [94]

Answer:

George is correct

Step-by-step explanation:

if the jacket is in sales for 20% off, Jane's coupon would give her a discount of 10% on top of the already discounted 20%.

Jane is incorrect because, if she added the 2 discount together, she gets a total of 30%, but that is a 30% discount of the original price of $75 which isn't correct. what we want to do is find how much the jacket cost after 20% discount THEN use the coupon to get a further 10% discount on the sales price of the jacket. and for this reason, George is correct.

hope this helped

3 0

3 years ago

Draw a triangle that is both a right triangle and an isosceles triangle. You can use either pencil and paper, or a draw program.

dem82 [27]

2. measurements can be any to complementary angles.
for example, 60 & 30
3. the 2 sides are equal. Since it is an isosceles triangle.
4.an equi.triangle can never be right angled. Since, all angles are 60° in an equi.triangle.
5. right triangle can never have an obtuse angle since one angle is already 90°. therefore the other two agles are supposed to be acute angles.[ since sum of all angles in a triangle is 180°]

6 0

3 years ago

Given f of x is equal to 1 over the quantity x minus 3 end quantity and g of x is equal to the square root of the quantity x plu

Lostsunrise [7]

The domain of the composite function is given as follows:

[–3, 6) ∪ (6, ∞)

<h3>What is the composite function of f(x) and g(x)?</h3>

The composite function of f(x) and g(x) is given as follows:

$(f \circ g)(x) = f(g(x))$

In this problem, the functions are:

$f(x) = \frac{1}{x - 3}$ .

$g(x) = \sqrt{x + 3}$

The composite function is of the given functions f(x) and g(x) is:

$f(g(x)) = f(\sqrt{x + 3}) = \frac{1}{\sqrt{x + 3} - 3}$

The square root has to be non-negative, hence the restriction relative to the square root is found as follows:

$x + 3 \geq 0$

$x \geq -3$

The denominator cannot be zero, hence the restriction relative to the denominator is found as follows:

$\sqrt{x + 3} - 3 \neq 0$

$\sqrt{x + 3} \neq 3$

$(\sqrt{x + 3})^2 \neq 3^2$

$x + 3 \neq 9$

$x \neq 6$

Hence, from the restrictions above, of functions f(x), g(x) and the composite function, the domain is:

[–3, 6) ∪ (6, ∞)

More can be learned about composite functions at brainly.com/question/13502804

#SPJ1

7 0

2 years ago

Prove that BUGS is a trapezoid with coordinates B(-2,-1), U(0,3), G(3,2) and S(4,-3).

telo118 [61]

Answer:

Proved

Step-by-step explanation:

Given

$B =(-2,-1)$

$U = (0,3)$

$G = (3,2)$

$S = (4,-3)$

Required

Prove BUGS is a trapezoid

Given the coordinates, to prove a trapezoid; all we need to do is to check if one pair of sides is parallel.

Taking BU and GS as a pair

First, we calculate the slope using:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

For BU

$B =(-2,-1)$ --- $(x_1,y_1)$

$U = (0,3)$ --- $(x_2,y_2)$

So, we have:

$m = \frac{3 - -1}{0- -2}$

$m = \frac{4}{2}$

$m = 2$

For GS

$G = (3,2)$ --- $(x_1,y_1)$

$S = (4,-3)$ --- $(x_2,y_2)$

So, we have:

$m = \frac{-3-2}{4-3}$

$m = \frac{-5}{1}$

$m = -5$

The slope of BU and GS are not the same; hence, they are not parallel.

Taking BS and GU as a pair

Calculate the slope

For BS

$B =(-2,-1)$ --- $(x_1,y_1)$

$S = (4,-3)$ --- $(x_2,y_2)$

So, we have:

$m = \frac{-3 - -1}{4- -2}$

$m = \frac{-2}{6}$

$m = -\frac{1}{3}$

For GU

$G = (3,2)$ --- $(x_1,y_1)$

$U = (0,3)$ --- $(x_2,y_2)$

So, we have:

$m = \frac{3-2}{0-3}$

$m = \frac{1}{-3}$

$m = -\frac{1}{3}$

The slope of BS and GU are the same; hence, they are parallel.

BUGS is a trapezoid because BS and GU have the same slope

8 0

3 years ago

What type of correlation is shown? х xx Х X

Sladkaya [172]

No type of correlation is shown but do you have a graph

8 0

2 years ago