Write the equation of the line of best fit using the slope-intercept formula y=mx+b. Show all your work, including the points us
ed to determine the slope and how the equation was determined.
Points used to find the slope:
Slope:
Each step of my work to find the slope:
Equation for the line of best fit:
Each step of my work to find the equation:
What does the slope represent within the context of your graph?
What does the y-intercept represent?
Test the residuals of two other points to determine how well the line of best fit models the data.
Use the line of best fit to help you describe the correlation.
Using the line of best fit that you found in Part 3, Question 2, approximate how tall is a person whose arm span is 66 inches?
According to your line of best fit, what is the arm span of a 74-in-tall person?
Points used to find the slope:
Slope:
Each step of my work to find the slope:
Equation for the line of best fit:
Each step of my work to find the equation:
What does the slope represent within the context of your graph?
What does the y-intercept represent?
Test the residuals of two other points to determine how well the line of best fit models the data.
Use the line of best fit to help you describe the correlation.
Using the line of best fit that you found in Part 3, Question 2, approximate how tall is a person whose arm span is 66 inches?
According to your line of best fit, what is the arm span of a 74-in-tall person?
1 answer:
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Found this on socratic !!! hope this helps !!!!
Answer:
Step-by-step explanation:
Given that a popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams.
i.e. Sample mean = 1040 and
Sample std dev s = 25 gm
Sample size n = 100
Hence by central limit theorem we have the sample mean follows a normal distribution with mean =1040 and std dev = s = 25 gm
Normal curve would be with mean 1040 and std deviatin 25
b) P(X>1115)
= 1-0.9987
=0.0013
i.e. 0.13% would receive a bag that had a weight greater than 1115 grams