How do i prove that they are right triangles ?
2 answers:
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Answer:
Step-by-step explanation:
The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:
--------------------(i)
From the question,
the point is (5, 0, -6)
the plane is x + y + z = 6
Therefore,
a = 5
b = 0
c = -6
m = 1
n = 1
t = 1
r = 6
Substitute these values into equation (i) as follows;
Therefore, the shortest distance from the point to the plane is
Answer:
type 2 in the first box,
13/4 in the second box, and
-9/8 in the third one
Step-by-step explanation:Notice that you are asked to write the following quadratic expression in vertex form, so you need to find the "x" value of the vertex, and then the "y" value of the vertex:
Which in our case is: -13/4
and the value of the y for the vertex is obtained using the functional expression when x equals -13/4:
Then your expression for this quadratic should be:
Then type 2 in the first box, 13/4 in the second box, and -9/8 in the third one