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Shkiper50 [21]
3 years ago
9

Please help me out with this

Mathematics
1 answer:
Anettt [7]3 years ago
7 0

Answer:

81.75 ft²

Step-by-step explanation:

The area (A) of a trapezoid is calculated using the formula

A = \frac{1}{2} h (a + b)

where a, b are the parallel bases and h is the perpendicular height

Calculate h using the right triangle and the sine ratio

sin30° = \frac{opposite }{hypotenuse} = \frac{h}{10}

Multiply both sides by 10

10 × sin30° = h, thus

h = 5

a = 12 and b = 8.7 + 12 = 20.7, hence

A = \frac{1}{2} × 5 × (12 + 20.7)

   = 0.5 × 5 ×32.7

   = 81.75 ft²

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Answer:

Factory overhead is a liability account

6 0
3 years ago
Please help me !!!!<br> Will mark brainliest
stich3 [128]

Answer:

The value of x is 108°

Step-by-step explanation:

Given interior angles of parallelogram are:

\frac{2}{3}x, x, \frac{2}{3}x\ and x

<u>The sum of interior angles of a parallelogram is 360°.</u>

We will use this information to find the value of x.

So adding up all the angles and putting the sum equal to 360 we get,

x+\frac{2}{3}x+x+\frac{2}{3}x = 360

2x+\frac{2}{3}x+\frac{2}{3}x = 360\\2x + \frac{4}{3}x = 360

Taking LCM on left side of the equation, as it involves fraction

\frac{6x+4x}{3} = 360\\\frac{10x}{3} = 360

Multiplying both sides by 3

\frac{10x}{3} * 3 = 360 * 3\\10x = 1080

Dividing both sides by 10

\frac{10x}{10} = \frac{1080}{10}\\x = 108

Hence,

The value of x is 108°

3 0
3 years ago
A rectangular tank, 25 cm long and 25 cm wide is filled with water to a depth of 10 cm. When a metal cube of edge 10 cm is place
Sophie [7]

The problem involves the volume of the water of the rectangular tank, so first we must find the volume of our water. For the volume we have;

\begin{gathered} \text{Volume = Lenght x Width x Height} \\ V_{water}_{}_{}\text{ = 25 x 25 x 10} \\ V_{water}=6250cm^3 \end{gathered}

Therefore our tank has an initial volume of 6250 cm³, but if you drop a cube with a side measuring 10 cm. the volume of the water in our tank increases. Giving us the expression;

\begin{gathered} \text{Volume Combined = Volume of Water + Volume of Cube} \\ V_{comb}=V_{water}+V_{cube} \end{gathered}

Since we already have the volume of the water (which is 6250), we just need to find the volume of the cube using the same formula (<em>Volume = Lenght x Width x Height</em>);

\begin{gathered} V_{comb}=V_{water}+V_{cube} \\ V_{comb}=V_{water}+(Lenght_{cube})(Width_{cube})(Height_{cube})_{}_{}_{} \\ V_{comb}=V_{water}+10(10)(10) \\ V_{comb}=6250+1000 \\ V_{comb}=7250cm^3 \end{gathered}

Therefore our new volume when they are combined or when the cube is droped in the tank is 7250 cm³.

But we must remember since our tank would remain it's shape no matter how much water it holds it would always retain it's dimension of it's lenght and width (25x25), therefore it is possible to find the height of the new water level using this logic;

\begin{gathered} V_{comb}=(Length_{\tan k})(Width_{\tan k})(Height_{water}\text{)} \\ V_{comb}=(25)(25)(Height_{water})\text{ , with our }V_{comb}=7250 \\ 7250=625(Height_{water}) \\ \text{Height}_{water}=\frac{7250}{625} \\ \text{Height}_{water}=11.6\text{ cm} \end{gathered}

Therefore the height of the new water level is 11.6 cm.

7 0
1 year ago
Subtract.<br> 3- (-6)=<br> I’m not smart so plz just help!
RideAnS [48]

Answer:

9

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the value of f(-4) for the function f(x) = 3/2x-9 ?
oksian1 [2.3K]
F(x) = 3/2x - 9

f(-4) = 3/2(-4) - 9
f(-4) = -6 - 9
f(-4) = -15
7 0
3 years ago
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