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3 years ago

7

drag each label to the correct location on the image identify the characteristics and examples of career pathways and programs o

f study

1 answer:

Ray Of Light [21]3 years ago

6 0

career pathway is bottom right, bottom left. and top right and top left are program study.

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Use the law of conservation of energy (assume no friction nor air resistance) to determine the kinetic and potential energy at t

slava [35]

Answer:

Part A

1) At the starting point, we have;

PE = 40,000 J

2) PE = 0 J, KE = 40,000 J

3) KE = 20,000 J

4) PE = 15,000 J

5) KE = 32,500 J

6) KE = 40,000 J, PE = 0 J

7) KE = 35,000 J

8) KE = 40,000 J, PE = 0 J

Part B

The total Mechanical Energy = ME = 40,000 J

At the final point, we have;

ME = KE + PE = 40,000 J + 0 J = 40,000 J

Explanation:

Part A

By the law of conservation of energy, we have;

ME = PE + KE

Where;

ME = The total Mechanical Energy of the system

PE = The Potential Energy of the system

KE = The Kinetic Energy of the system

Where there is no friction, we have;

At the final stage, KE = 40,000 J. PE = 0 J

Therefore, ME = PE + KE = 40,000 J + 0 J = 40,000 J

1) At the starting point, we have;

KE = 0 J, therefore, PE = ME - KE = 40,000 J - 0 J = 40,000 J

2) At the bottom of the roller coaster, at the same level the PE is taken as PE = 0 J at the final stage, we have;

PE = 0 J, therefore, KE = ME - PE = 40,000 J - 0 J = 40,000 J

3) Where PE = 20,000 J, KE = ME - PE = 40,000 J - 20,000 J = 20,000 J

4) Where KE = 25,000 J, PE = ME - KE = 40,000 J - 25,000 J = 15,000 J

5) Where PE = 7,500 J, KE = ME - PE = 40,000 J - 7,500 J = 32,500 J

6) At the bottom KE = 40,000 J, PE = 0 J

7) Where PE = 5,000 J, KE = ME - PE = 40,000 J - 5,000 J = 35,000 J

8) KE = 40,000 J, PE = 0 J

Part B

The given that there is no friction nor air resistance, the total Mechanical Energy, ME, is constant and equal to the sum of the Potential Energy, PE and the Kinetic Energy, KE, as follows;

ME = KE + PE

At the final point, we have;

ME = 40,000 J + 0 J = 40,000 J

The total Mechanical Energy = ME = 40,000 J

8 0

2 years ago

If i go to the moon what happens to my mass and weight

mixas84 [53]

Your mass stays the same because mass is the matter of something so the only way it could be changed is if you cut off something

Your weight changes because the gravitational field strength of different

6 0

3 years ago

A Venn diagram is used to compare and contrast different topics. The items that are unique to each topic are represented in the

Ahat [919]

Endothermic: ice melting into water, and an instant ice pack turning cold

Exothermic: fireworks exploding, and gasoline burning

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3 years ago

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4. In a object filled with a type of gas, which of the following actions would decrease the pressure

ExtremeBDS [4]

Answer:

Decrease the number of gas particles, increase the object's area, and reduce the temperature of the gas

Explanation:

<u>TEMPERATURE</u>:

Decreasing the temperature will slow down the molecules. Hence, less no. of collisions will take place between walls of object and molecules. This will result in decrease of pressure.

Therefore, the pressure of a gas can be decreased by increasing its temperature.

<u>NUMBER OF GAS PARTICLES</u>:

Decreasing the number of particles will result in less no. of collisions, hence decreasing the pressure.

Therefore, the pressure of a gas can be decreased by decreasing its no. of molecules or no. of particles.

<u>AREA OF OBJECT:</u>

The pressure is given by the formula:

$P = \frac{F}{A}\\\\For constant Force (F):\\P\ \alpha\ \frac{1}{A}$

where,

A = Area of Object

Therefore, the pressure of a gas can be decreased by increasing area of object.

So, the correct option is:

<u>Decrease the number of gas particles, increase the object's area, and reduce the temperature of the gas</u>

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3 years ago

Which of the following is a common property of Noble Gases?

Softa [21]

<span>Have a full outer shell of electrons.</span>

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3 years ago

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