Answer:
Car first should be 30.13 m behind the second car.
Explanation:
Given that,
Constant speed = 108.5 Km/hr
Time = 1 sec
Let the distance covered by second car S and by first car S'
We need to calculate the distance covered by second car
Using equation of motion
.....(I)
The distance covered by first car to avoid collision

Put the value into the formula
...(II)
We need to calculate the distance covered by first car
Using equation (I) and (II)

Put the value into the formula


Hence, Car first should be 30.13 m behind the second car.
Answer: 5 m
Explanation:
We have the following data:
is the intensity of the sound at 7.5 m from the source
is the distance at which the intensity
was measured
is the intensity of the sound at
from the source
We have to find 
Since the object is radiating the signal uniformly in all directions, we can use the <u>Inverse Square Law for Intensity:</u>

Isolating
:


This is the distance at which the intensity is the "threshold of pain"
Now, we have to substract this value to
to find how much closer to the source can we move:

Period and frequency are mutual reciprocals.
Period = 1 / frequency .
Frequency = 1 / period
(Frequency) x (Period) = 1
Two colliding objects will exert equal forces upon each other. If the objects have different masses, then these equal forces will produce different accelerations.
Answer:
A neutral object has the same charge. A positively charged object have positive charges called electrons. A negatively charged object have negative charges called protons.
Diagram of each down below -