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3 years ago

During an experiment, a student moved a cell from pure water to salted water. What will most likely happen to the cell?

Physics

1 answer:

jarptica [38.1K]3 years ago

5 0

Answer:

During an experiment, a student moves a cell from pure water to salted water. ... It will release water and shrivel. It will release water and burst.

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If you added 5 x more mass into a wheelbarrow, how much greater would

aev [14]

Answer:

5 x biger

Explanation:

becuze if it ia 5× more it nids 5×more force to be =

7 0

3 years ago

A sample of an ideal gas has a volume of 2.37 L at 2.80×102 K and 1.15 atm. Calculate the pressure when the volume is 1.68 L and

iogann1982 [59]

Answer:

$p_2 = 1.76 atm$

Explanation:

given data:

v_1 = 2.37 L

v_2 = 1.68 L

p_1 =1.15 atm

p_2 = ?

t_1 = 280 K

t_2 = 304 K

from Gas Law Equation

, WE HAVE

$\frac{p_1 v_1}{t_1} =\frac{p_2 v_2}{t_2}$

Putting the values

$\frac{1.15*2.37}{280} =\frac{p_2 *1.68}{304}$

$9.733*10^{-3} = \frac{p_2 *1.68}{304}$

$9.733*10^{-3}*304 = p_2*1.68$

$\frac{9.733*10^{-3}*304}{1.68} =p_2$

$p_2= 1.76 atm$

7 0

3 years ago

A fixed mass of an ideal gas is heated from 50°C to 80°C (a) at constant volume and (b) at constant pressure. For which case do

soldi70 [24.7K]

Answer:

Specific heat at constant pressure is = 1.005 kJ/kg.K

Specific heat at constant volume is = 0.718 kJ/kg.K

Explanation:

given data

temperature T1 = 50°C

temperature T2 = 80°C

solution

we know energy require to heat the air is express as

for constant pressure and volume

Q = m × c × ΔT ........................1

here m is mass of the gas and c is specific heat of the gas and Δ T is change in temperature of the gas

here both Mass and temperature difference is equal and energy required is dependent on specific heat of air.

and here at constant pressure Specific heat is greater than the specific heat at constant volume,

so the amount of heat required to raise the temperature of one unit mass by one degree at constant pressure is

Specific heat at constant pressure is = 1.005 kJ/kg.K

and

Specific heat at constant volume is = 0.718 kJ/kg.K

3 0

3 years ago

Identify and sketch all the external forces acting on the chair. because the chair can be represented as a point particle of mas

SOVA2 [1]

There are two external force acts on the chair.

1. The force due to earth gravity, acts in the downward direction.

2. Reaction force of the gravity, which acts in the Upward direction (Normal Force).

On every object, there is a force acts due to gravity of earth, which pulls the object towards the centre of earth, known as gravity force, always acts in the downward direction. Mathematically it's given as

F=mg

here, m is the mass of the object, and g is the acceleration of gravity.

To balance this gravity force, a counter force acts in the opposite direction, whose magnitude is equal to the force of gravity

8 0

3 years ago

Read 2 more answers

The graph represents the force applied on an 3.00kg crate while it moved 5.0m. A. How much total work is done on the crate? B. I

jeka57 [31]

a. We can calculate the amount of work by calculating the area under the graph.

first area (rectangular): 2.5 x 6 = 15

second area(trapezoid): 1/2 x (6+10) x 2.5 =20

total work done: 35 J

b. the force was first applied = 6 N

F = m.a

a = 6 : 3 = 2 m/s²

vf²=vi²+2as

vf²=6²+2.2.5

vf²=56

vf=7.5 m/s

8 0

3 years ago