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fiasKO [112]
3 years ago
8

3. Fill in: Name the organelle or organelles that perform each of the following functions.

Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
8 0

A. Chloroplasts

B. The cell wall and the vacuole

C. Vacuoles

D. The mitochondrion

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Gold (Au) is considered a(n)<br><br><br> Compound<br><br> Potatoes<br><br> Mixture<br><br> Element
strojnjashka [21]

Answer:

Element

Explanation:

The symbol for gold is Au which only has one capital letter. This means that there is only one thing that makes up gold which would make it an element.

hope this helps :)

3 0
3 years ago
A chemist heats a sample of hydrated lithium nitrate which weighs 170 grams and finds, after heating that it weighs 95.3 grams.
Agata [3.3K]

Explanation:

170-95.3 = 74.7

that means

74.7% of water in hydrate

7 0
3 years ago
Explain how you would make 450 mL of a .250M NaOH solution?
Neporo4naja [7]

Answer:

Weigh 4.5 grams of sodium hydroxide and add it to the dry volumetric flask of 450 mL followed by small amount of water to dissolve all the NaOH .After this add the water upto tye mark of 450 mL.

Explanation:

Molarity of the solution is the moles of compound in 1 Liter solutions.

Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}

Mass of NaOH = x

Molar mass of NaOH = 40 g/mol

Volume of the NaOH solution =  450 mL =- 0.450 L ( 1 ml = 0.450 L)

Molarity of the solution of NaOH = 0.250 M

Molarity=\frac{1.248 g}{26 g/mol\times 0.9102254 L}=0.528 mol/L

0.250 M=\frac{x}{40 g/mol\times 0.450 L}

Solving for x:

x = 4.5 g

Weigh 4.5 grams of sodium hydroxide and add it to the dry volumetric flask of 450 mL followed by small amount of water to dissolve all the NaOH .After this add the water upto tye mark of 450 mL.

4 0
3 years ago
A concentration cell is constructed by using the same half-reaction for both the cathode and anode. What is the value of standar
Akimi4 [234]

Solution :

A cell that is concentrated is constructed by the same half reaction for the anode as well as he cathode.

We know,

In a standard cell,

the reduction half cell reaction is :

$Ag^+(aq)+e^- \rightarrow Ag(s) E^0 = -0.80 \ V$

The oxidation half ell reaction :

$Ag(s) \rightarrow Ag^+(aq) + e^- \ E^0= +0.80 \ V$

Thus the complete reaction of the cell is :

$Ag^+(aq)+ Ag(s) \rightarrow Ag^+(aq)+Ag(s)$

$E^0 $ cell = $E_R - E_L = 0.00  \ \text{volts}$

7 0
3 years ago
Lil give brainly 20 points
torisob [31]

Answer: i would say producer

Explanation:

7 0
2 years ago
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