The mixture flow rate in lbm/h = 117.65 lbm/h
<h3>Further explanation</h3>
Given
15.0 wt% methanol
The flow rate of the methyl acetate :100 lbm/h
Required
the mixture flow rate in lbm/h
Solution
mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :
![\tt 15\%\times 200~kg=30~kg\\\\mol=\dfrac{mass}{MW}=\dfrac{30~kg}{32~kg/kmol}=0.9375~kmol](https://tex.z-dn.net/?f=%5Ctt%2015%5C%25%5Ctimes%20200~kg%3D30~kg%5C%5C%5C%5Cmol%3D%5Cdfrac%7Bmass%7D%7BMW%7D%3D%5Cdfrac%7B30~kg%7D%7B32~kg%2Fkmol%7D%3D0.9375~kmol)
mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :
![\tt 85\%\times 200=170~kg\\\\mol=\dfrac{170}{74}=2.297~kmol](https://tex.z-dn.net/?f=%5Ctt%2085%5C%25%5Ctimes%20200%3D170~kg%5C%5C%5C%5Cmol%3D%5Cdfrac%7B170%7D%7B74%7D%3D2.297~kmol)
Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.
1 kg mixture = 0.85 .methyl acetate
So flow rate for mixture :
![\tt \dfrac{1~kg~mixture}{0.85~methyl~acetat}\times 100~lbm/h=117.65~lbm/h](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B1~kg~mixture%7D%7B0.85~methyl~acetat%7D%5Ctimes%20100~lbm%2Fh%3D117.65~lbm%2Fh)
Answer:
1. bitter
2. turns litmus paper red
3. oxygen, hydrogen, and molecules.
Explanation:
Answer: the coefficient of volume expansion of glass = 0.86/(1000 * 52) = 0.00001654 per degree.
Explanation:
Original volume of mercury = 1000 cm3.
The final volume of mercury considering its volume expansion quotient = 1000 + 1000*(1.8*10^-4 *52) = 1000 + 9.36 = 1009.36 cm^3
Considering the glass as a non expanding substance, the complete excess volume of 9.36 cm3 of mercury should have overflown the container, but due to the expansion of glass, the capacity of mercury containment increases and so a lesser amount of mercury flows out.
The amount of mercury that actually flowed out = 8.50 cm3.
So, the expansion of the glass container = 9.36-8.50 = 0.86 cm3.
Using the formula for coefficient of expansion,
coefficient of volume expansion of glass = 0.86/(1000 * 52) = 0.00001654 per degree.