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spin [16.1K]
3 years ago
14

What is the slope of the line that is parallel to the line represented by the equation below? 4x-5y=-1 A. 4/5 B. -4/5 C. 5/4 D.

-5/4
Mathematics
1 answer:
Anna71 [15]3 years ago
3 0
A. 4/5

To find the slope, you need to isolate y.

4x-5y=-1

-5y= -1-4x (or -4x-1)

-y= (-4/-5)x-1/-5

y=4/5x+1/5
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Answer:

  • The angle ∠1 = x = 36°
  • The angle ∠2 = 4x = 4(36°) = 144°

Step-by-step explanation:

We know that when two lines meet or intersect, we get a linear pair of angles.

Linear pairs are basically two adjacent angles that form a line.

The measure of two adjacent angles forming a straight line is 180, meaning they are supplementary.

We are given that <1 and <2 forms a linear pair, and

m∠1 = 4m∠2

It means the angle ∠1 is 4 times the measure of angle ∠2.

Let the angle ∠1 be = x

As the angle 1 is 4 times the measure of angle ∠2, so

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As <1 and <2 forms a linear pair, thus the measure of the sum of <1 and <2 will be 180°, so

x + 4x = 180

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divide both sides by 5

5x/5 = 180/5

x = 36°

Therefore,

  • The angle ∠1 = x = 36°
  • The angle ∠2 = 4x = 4(36°) = 144°
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