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Nadusha1986 [10]
3 years ago
11

What is one ecosystem you can think of? What non-living and living things are found in your ecosystem?

Chemistry
1 answer:
kkurt [141]3 years ago
5 0
A swamp. There are frogs, snakes, alligators, etc... and on behalf of the non living things in my ecosystem consist of leaves, lily pads and moss.
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According to the Lewis dot structure shown here, how many valence electrons does chlorine have?
trasher [3.6K]
Chlorine has 7 valence electrons
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3 years ago
4. Is the ketone oxidized or reduced during this reaction and how can you tell?
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5. Azulene is a beautiful blue hydrocarbon. If 0.106 g of the compound is burned in oxygen, 0.364 g of CO2 and 0.0596 g of H2O a
max2010maxim [7]

<u>Answer:</u> The empirical and molecular formula for the given organic compound is CH and C_{10}H_{10} and it is not an alkane.

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=0.364g

Mass of H_2O=0.0596g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.364 g of carbon dioxide, \frac{12}{44}\times 0.364=0.0993g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0596 g of water, \frac{2}{18}\times 0.0596=0.0067g of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0993g}{12g/mole}=0.00828moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.0067g}{1g/mole}=0.0067moles]

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0067 moles.

For Carbon = \frac{0.00828}{0.0067}=1.23\approx 1

For Hydrogen = \frac{0.0067}{0.0067}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is CH

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 128.2 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

n=\frac{128.2g/mol}{13g/mol}=9.86\approx 10

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(1\times 10)}H_{(1\times 10)}=C_{10}H_{10}

The general formula of an alkane is C_nH_{(2n+2)}, where n = any natural number

Here, n = 10 and it does not satisfy being an alkane

Hence, the empirical and molecular formula for the given organic compound is CH and C_{10}H_{10} and it is not an alkane.

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Subtract to find the temperature changes<br><br> for the water and the metal.
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From smallest to largest put these in order of their atomic radius Mg, Ba,
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Answer:

b

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i jus did it

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