Answer:
The electron cloud is mostly empty space
Answer:
Being a plane mirror the Image is formed 3 metres beyond the mirror . So total distance is 3+3 = 6metres
Answer:
The electric field strength at the midpoint of the line joining the charges is zero (0)
Explanation:
Given that the two charges are both positive (same charge) and are equal in magnitude that is 6uC. The electric field strength at the midpoint of the line joining the two charges will be equal and opposite in magnitude, therefore they will cancel each other out and the electric field strength at this point will be equal to zero.
1. 12.75 J
Assuming that the force applied is parallel to the ramp, so it is parallel to the displacement of the cart, the work done by the force is
![W=Fd](https://tex.z-dn.net/?f=W%3DFd)
where
F = 15 N is the magnitude of the force
d = 85 cm = 0.85 m is the displacement of the cart
Substituting in the formula, we get
![W=(15 N)(0.85 m)=12.75 J](https://tex.z-dn.net/?f=W%3D%2815%20N%29%280.85%20m%29%3D12.75%20J)
2. 10.6 N
In this part, the cart reaches the same vertical height as in part A. This means that the same work has been done (because the work done is equal to the gain in gravitational potential energy of the object: but if the vertical height reached is the same, then the gain in gravitational potential energy is the same, so the work done must be the same).
Therefore, the work done is
![W=Fd=12.75 J](https://tex.z-dn.net/?f=W%3DFd%3D12.75%20J)
However, in this case the displacement is
d = 120 cm = 1.20 m
Therefore, the magnitude of the force in this case is
![F=\frac{W}{d}=\frac{12.75 J}{1.20 m}=10.6 N](https://tex.z-dn.net/?f=F%3D%5Cfrac%7BW%7D%7Bd%7D%3D%5Cfrac%7B12.75%20J%7D%7B1.20%20m%7D%3D10.6%20N)