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serg [7]
3 years ago
11

15) In which of the following cases would sound reach each ear out of phase? A. You are standing directly in front of the sound

source. B. You are standing directly below the sound source. C. You are standing directly to the right of the sound source. D. You are standing directly behind the sound source.
16) In which of the following cases would sound reach each ear out of phase? A. You are standing directly in front of the sound source.
B. You are standing directly below the sound source.
C. You are standing directly to the right of the sound source.
D. You are standing directly behind the sound source.
Physics
2 answers:
Sonja [21]3 years ago
7 0

In one of the greatest coincidences to arise on Brainly in quite some time, Choice-C is the correct choice for BOTH #15 and #16 .

Choice-C is the only situation in which the source is a different distance from each ear.

Oksana_A [137]3 years ago
5 0

Answer:

(15)The sound will reach ear out of phase when you are standing directly to the right of sound source.

Because when we are behind or in front distance between both the ear to the sound source will be same.

Therefore, Option C is correct.

(16) The sound  source will reach ear out of phase when you are standing directly to the right of sound source.

Therefore, option C is correct.

Both questions have same information.

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A convex mirror, like the passenger-side rearview mirror on a car, has a focal length of -3.0 m . An object is 6.0 m from the mi
Artist 52 [7]

A) -2.0 m

Look at the ray diagram attached in the picture, where:

p identifies the location of the object

q identifies the location of the image

F identifies the focus of the mirror

Each tick represents 1 m

We have

p = 6.0 m is the distance of the object from the mirror

f = -3.0 m is the focal length

From the ray diagram, we see that q has a distance of 2.0 m from the mirror, and it's on the other side of the mirror compared to the object, so

q = -2.0 m

This can also be verified by using the mirror equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-3.0 m}-\frac{1}{6.0 m}=-\frac{3}{6.0 cm}\\q = \frac{-6.0 cm}{3}=-2.0 cm

B) Upright and virtual

As we see from the picture, the image is upright, since it has same orientation as the object.

Also, we notice that the image is on the other side of the mirror, compared to the object. For a mirror,

- An image is said to be real if it is on the same side of the object

- An image is said to be virtual if it is on the opposite side of the mirror

Therefore, this means that the image is virtual.

8 0
3 years ago
A train of mass 5.6 × 10^5kg is at rest in a station.at time t=0s, a resultant force acts on the train and it starts to accelera
lana66690 [7]

Answer:

420000N

Explanation:

Given parameters:

Mass of the train  = 5.6 x 10⁵kg

Acceleration  = 0.75m/s²

Unknown:

Resultant force = ?

Solution:

According to newton's second law, force is the product of mass and acceleration;

   Force  = mass x acceleration

Resultant force that acts on the train is given below;

 Force  = 5.6 x 10⁵kg  x 0.75m/s²  = 420000N

7 0
3 years ago
How is the surface area of an average person is 2m^2 in the chapter pressure
11Alexandr11 [23.1K]

Answer:

We have to show surface area =2m^2,with few conditions that is by considering Force =200000\ N and Pressure =100000\ Pa to be respectively.

Explanation:

The atmospheric pressure is =10^{5}\ Pa on Earth's surface.

The magnitude of the force exerted on a person by the atmosphere is =2\times 10^{5}\N (or)\ 200kN\ (or)\ 20\ ton.

Now to calculate surface area we can find it from pressure=\frac{force}{area} and re-arranging it to.

area=\frac{force}{pressure}

So plugging the values,

Surface area =\frac{20000}{10000}=2\ m^{2}

Hence from the above calculations we can say that surface area is 2m^2.

So the surface area of an average person can be said to have 2m^2, using the concept of pressure and force.

3 0
3 years ago
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olga_2 [115]

Answer:

298800 m

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v =  \frac{d}{t}

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t=time

d = vt

Change hours to seconds

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8 0
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Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals that scientists d
n200080 [17]
The scientists describe them as D. Elliptical
5 0
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