I believe the answer would be zero because the q1 and q2 are equal on opposite sides and it
hope this helps
Complete question:
A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from the bulb, the amplitude of the electric field is 3.78 V/m. What is the average intensity of the light?
Answer:
The average intensity of the light is 0.02 W/m²
Explanation:
Given;
Amplitude of the electric field, E₀ = 3.78 V/m
The average intensity of the light is calculated as follows;
where;
is the average intensity of the light
c is speed of light = 3 x 10⁸ m/s
Therefore, the average intensity of the light is 0.02 W/m²
The atmosphere absorbs most of the solar RADIATION in the atmosphere, but not all which is how we still get sun burns. :)
1)
<Solve using the formula which is:
Mass=Density×Volume
2)
3)
(Length × Width × Height)
(Answer=7.5)
Answer:
<em>Answer: Both move with constant speed.</em>
Explanation:
<u>Constant Speed Motion
</u>
When an object moves in such a way that it travels the same distances at the same times, we can say its speed is constant. For example, if it travels x=10 m in t=2 seconds and later it travels x=20 m in t=4 seconds, its speed is constant and equal to v=5 m/s. The relation between the variables x,t, and v is
x=v.t
Note that the relation between x and t is v, a constant value, thus the graph x-t is a line.
The question describes two graphs, for Object A and Object B respectively, and both of the descriptions correspond to lines. We don't have much information about the characteristics of the lines, but we can be sure, according to the definitions stated above, that both objects are traveling at a constant speed.
Answer: Both move with constant speed.
