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4 years ago

A ball has a diameter of 3.79 cm and average density of 0.0838 g/cm3.

Physics

1 answer:

suter [353]4 years ago

3 0

Answer: 0.258 N

Explanation:

As the density of the object is much less than the density of water, it’s clear that the buoyant force, is greater than the weight of the object, which means that in normal conditions, it would float in water.

So, in order to get the ball submerged in water, we need to add a downward force, that add to the weight, in order to compensate the buoyant force, as follows:

F = Fb – Fg

Fb= δH20* 4/3*π*(d/2)³ * g

Fg = δb* 4/3*π*(d/2)³ *g

F= (δH20- δb) * 4/3*π*(d/2)³*g

Replacing by the values of the densities, and the ball diameter, we finally get:

F= 0.258 N

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Answer:

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Explanation:

The equation we know for speed is speed = distance/time, shortened to s = d/t

If you want to find the distance, you'd rearrange the formula to make d the subject. To isolate d, multiply by t on both sides (since it's being divided on the right. This leads to

s x t = d, with d isolated on the right side.

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3 years ago

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4 years ago

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lukranit [14]

Answer:

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3 years ago

A home uses ten 100-watt lightbulbs for five hours per day. Approximately how many kilowatt-hours of electrical energy are consu

timurjin [86]

The electrical energy consumed in one year by using the light bulbs is 8,760 kWh.

The given parameters:

Number of light bulbs = 10
Power consumed by each bulb = 100 W
Time of energy consumption, t = 1 year

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This is the electric power consumed or dissipated at a given period of time.

The electrical energy consumed in one year by using the light bulbs is calculated as

E = Pt

$E = (100 \times 10) \times (1 \ yr \times \frac{8760 \ hrs}{1 \ yr} )= 8,760,000 \ W att-hours\\\\
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Thus, the electrical energy consumed in one year by using the light bulbs is 8,760 kWh.

Learn more about electrical energy here: brainly.com/question/60890

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