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3 years ago

Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.

Mathematics

1 answer:

Charra [1.4K]3 years ago

5 0

Answer:

the download cost for a song is $1 and $11 for a movie

Step-by-step explanation:

According to the questions, the following equations are as follows:

Let us assume the song be x

And, the movies be y

So,

20x + 13y = $163.........(i)

13x + 13y = $156........(ii)

Now solve substract second equation from the first equation

7x = $7

x = $1

And the y value is

20 + 13y = $163

13y = $163 - $20

13y = $143

y = $11

Hence, the download cost for a song is $1 and $11 for a movie

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Satnam is making a cake. he uses a batter made of 150g of dry ingredients.if the liquid has to be two sevenths of the total weig

SIZIF [17.4K]

Answer:

Answer- 85.7 g

300:7= 42.85

42.85x2=85.7

Step-by-step explanation:

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3 years ago

Read 2 more answers

A battery is charged. The percentage of the battery’s capacity that is charged as a function of time (in minutes) is graphed.

igor_vitrenko [27]

Answer:

A- 12 percent

Step-by-step explanation:

You can see on the graph that the charged percentage of capacity changes from 40 to 50 in 5 minutes. Then the increase in 6 minutes will be slightly more than 10 percent.

The linear rate is (10%)/(5 min) = 2%/min, so in 6 minutes it will be

(2%/min)×(6 min) = 12%

This calculation is consistent with our observation from the graph.

Every 6 minutes, 12 percent is added to the capacity.

3 0

3 years ago

Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

mart [117]

Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

$\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}$

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

$\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}$ $[\because a^ma^n=a^{m+n}]$

$\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}$

$\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

5 0

3 years ago

Mikhail believes he can use the multiplication expression 1/2x6 to find the total number of

Svetlanka [38]

Answer:

I think the second option is the most appropriate option.

Step-by-step explanation:

Mikhail believes he can use the multiplication expression $\frac{1}{2} \times 6$ to find the total number of pound servings of rice he can make from 6 pounds of rice.

Now, we have to select the statement from the four options that best explains why Mikhail is correct or incorrect.

I think the second option is the most appropriate option.

So, Mikhail is correct in using a multiplication expression because 1/2 is the number of servings per pound. (Answer)

7 0

3 years ago

Pls help me find the equation and do the table

Goryan [66]

Check the picture below.

$20 when the hours is 0, is pretty much just a base fee Andy has before doing any on location hours of work, namely is a fee the customer owes for the service before anything else, usually is for paperwork required for hte contract.

4 0

3 years ago