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inn [45]
3 years ago
6

Six more than three times a number is less than or equal to 69

Mathematics
1 answer:
Reika [66]3 years ago
5 0
The answer would be less. Hope this helps. :)
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How many times dose 18 go into 170
Leokris [45]
I think it is 10 because 18×10=180 but it is close hope this helps
7 0
3 years ago
A salesman's commission on 150,000 sale is 3000. what is the percent?
fomenos
The percentage is 98%.

You can find this by multiplying 98% (0.98) and 150,000 to get 147,000. Then subtract 147,000 from 150,000 to get 3,000.

I hope this helps!
8 0
3 years ago
How cos π/3=1/2?<br>having some problems learning continuity.
Bingel [31]

You can show that \cos\frac\pi3=\frac12 by constructing a triangle.

Take two points, O(0, 0) and A(1, 0), and let B be the point on the unit circle such that the angle between the line segments OA and OB is \frac\pi3 radians.

Since both A and B lie on the circle, the line segments OA and OB both have length 1 (same as the circle's radius). We finish constructing the triangle by connect A and B.

Since OB and OA have the same length, triangle OAB is isosceles, but more than that, it's also equilateral. Why? Because the interior angles of any triangle always add to \pi radians. We know one of the angles is \frac\pi3 radians, which leaves a contribution of \frac{2\pi}3 radians between the remaining angles A and B. Angles A and B must be congruent (because OAB is isosceles), which means they also have measure \frac\pi3 radians.

Next, draw an altitude of the triangle through point B, and label the point where it meets the "base" OA, C. Since OAB is equilateral, the altitude BC is also a perpendicular bisector. That means OC has length \frac12, and by definition of \cos we have

\cos\dfrac\pi3=\dfrac{OC}{OB}=\dfrac{\frac12}1=\dfrac12

3 0
3 years ago
Can you help me find t value in this problem?
Eduardwww [97]

we have a maximum at t = 0, where the maximum is y = 30.

We have a minimum at t = -1 and t = 1, where the minimum is y = 20.

<h3>How to find the maximums and minimums?</h3>

These are given by the zeros of the first derivation.

In this case, the function is:

w(t) = 10t^4 - 20t^2 + 30.

The first derivation is:

w'(t) = 4*10t^3 - 2*20t

w'(t) = 40t^3 - 40t

The zeros are:

0 = 40t^3 - 40t

We can rewrite this as:

0 = t*(40t^2 - 40)

So one zero is at t = 0, the other two are given by:

0 = 40t^2 - 40

40/40 = t^2

±√1 = ±1 = t

So we have 3 roots:

t = -1, 0, 1

We can just evaluate the function in these 3 values to see which ones are maximums and minimums.

w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20

w(0) = 10*0^4 - 20*0^2 + 30    = 30

w(1) =  10*(1)^4 - 20*(1)^2 + 30 =  20

So we have a maximum at x = 0, where the maximum is y = 30.

We have a minimum at x = -1 and x = 1, where the minimum is y = 20.

If you want to learn more about maximization, you can read:

brainly.com/question/19819849

6 0
2 years ago
Answer please, id appreciate some help:)?
Tems11 [23]
I believe that the answer is c but if you wanted to make sure you could figure out the correlation on a graphing calculator.
3 0
3 years ago
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