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Komok [63]
3 years ago
5

A technician has verified that a recent loss of network connectivity to multiple workstations is due

Physics
1 answer:
Natasha_Volkova [10]3 years ago
8 0

Answer:

D. Toner probe

Explanation:

The tone probe allows you to apply a tone signal to a pair of wires or a single conductor, while the trace is done with an amplified probe. When used in conjunction with the amplified probe, the tone generator allows technicians to identify a wire within any beam, at cross connections or at remote ends. You can use twisted pair, coaxial and disconnected AC wiring.

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When work is done and a force is transferred which choice describes the movements of the object?
Arisa [49]
When work is done and a force is transferred an object must move
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4 years ago
Explain how machines can be useful if the output is always less than the input work
Anni [7]

Because: Some of the work done by the machine is used to overcome the friction created by the use of the machine. ... Work output can never be greater than work input. Machines allow force to be applied over a greater distance, which means that less force will be needed for the same amount of work.

6 0
3 years ago
If I toot 88 times what did that mean
Degger [83]

Answer:Nazi skinhead code for Heil Hitler. H being the 8th letter of the alphabet, therefore HH=88.

Explanation:

8 0
3 years ago
The atomic radii of Mg2+ and F- ions are 0.072 and 0.133 nm, respectively.(a) Calculate the force of attraction between these tw
timurjin [86]

Answer:

1.09527\times 10^{-8}\ N

Explanation:

q_1 = Mg ion = +2q

q_2 = F ion = -q

q = Charge of electron = 1.6\times 10^{-19}\ C

r = Distance between ions = 0.072+0.133\ nm

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

Electrical force is given by

F=-\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=-\dfrac{8.99\times 10^9\times 2\times 1.6\times 10^{-19}\times -1\times 1.6\times 10^{-19}}{[(0.072+0.133)\times 10^{-9}]^2}\\\Rightarrow F=1.09527\times 10^{-8}\ N

The attractive force is 1.09527\times 10^{-8}\ N

8 0
4 years ago
Suppose a tidal basin is 6 m above the ocean at low tide and that the area of the basin is 5×107 m2. Estimate the gravitational
Neko [114]

Answer:

Potential energy will be 176.58\times 10^{11}j          

Explanation:

We have given the height of the basin is h = 6 m

Area of the basin A=5\times 10^7m^2

Volume V=area \times height=5\times 10^7\times 6=30\times 10^7m^3

Density \rho =1000kg/m^3

We know that mass is given by m=\rho V=1000\times 30\times 10^7=3\times 10^{11}kg

We know that potential energy is given by E=mgh=3\times 10^{11}\times 9.81\times 6=176.58\times 10^{11}j

3 0
3 years ago
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