Answer:
a)
b)S= 46.4 cm
Explanation:
Given that
Velocity = 16 Km/s
V= 16,000 m/s
E= 27 mV/m
E=0.027 V/m
d= 22.5 cm
d= 0.225 m
a)
lets time taken by electron is t
d = V x t
0.225 = 16,000 t
b)
We know that
F = m a = E q ------------1
Mass of electron ,m
Charge on electron
So now by putting the values in equation 1
Here initial velocity u= 0 m/s
S=0.464 m
S= 46.4 cm
S is the deflection of electron.
Well i think it is false caus ebunch of products these day have metals incorparded in the product
A proton is held at rest in a uniform electric field. When it is released, the proton will lose its kinetic energy.
Kinetic energy
The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort when slowing down from its current pace to a condition of rest. Formally, kinetic energy is any term that includes a derivative with respect to time in the Lagrangian of a system.
To learn more about kinetic energy refer here:
brainly.com/question/11301578
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Answer:
Explanation:
Given that,
Mass of star M(star) = 1.99×10^30kg
Gravitational constant G
G = 6.67×10^−11 N⋅m²/kg²
Diameter d = 25km
d = 25,000m
R = d/2 = 25,000/2
R = 12,500m
Weight w = 690N
Then, the person mass which is constant can be determined using
W =mg
m = W/g
m = 690/9.81
m = 70.34kg
The acceleration due to gravity on the surface of the neutron star is can be determined using
g(star) = GM(star)/R²
g(star) = 6.67×10^-11 × 1.99×10^30 / 12500²
g (star) = 8.49 × 10¹¹ m/s²
Then, the person weight on neutron star is
W = mg
Mass is constant, m = 70.34kg
W = 70.34 × 8.49 × 10¹¹
W = 5.98 × 10¹³ N
The weight of the person on neutron star is 5.98 × 10¹³ N
