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Fed [463]
2 years ago
14

When you mix two substances, the heat gained by one substance is equalto the heat lost by the other substance. Suppose you place

125 g of aluminum ina calorimeter with 1,000 g of water. The water changes temperature by 2 °C andthe aluminum changes temperature by â74.95 °C.
Required:
a. Water has a known specific heat capacity of 4.184 J/g °C. Usethe specific heat equation to find out how much heat energy the watergained (q).
b. Assume that the heat energy gained by the water is equal to the heat energy lost by the aluminum. Use the specific heat equation to solve for the specific heat of aluminum. (Hint: Because heat energy is lost, the value of q is negative.)
Physics
1 answer:
Debora [2.8K]2 years ago
7 0

Answer:

A) 8,368 J

B) 0.893 J/gºC

Explanation:

A)

  • The heat gained by the water can be obtained solving the following equation:

       q_{g} = c_{w} * m *  \Delta T (1)

  • where cw = specific heat of water = 4.184 J/gºC
  • m= mass of water = 1,000 g
  • ΔT = 2ºC
  • Replacing these values in (1) we get:

       q_{g} = c_{w} * m *  \Delta T = 4.184 J/gºC*1,000 g* 2ºC = 8,368 J (2)

B)

  • Assuming that the heat energy gained by the water is equal to the one lost by the aluminum, we can use the same equation, taking into account that the energy is lost by the aluminum, so the sign is negative:  -8,368 J.
  • Replacing by the mass of aluminum (125 g), and the change in temperature (-74.95ºC), in (1), we can solve for the specific heat of aluminum, as follows:

       q_{l} = c_{Al} * m_{Al} *  \Delta T  (3)

⇒    -8,368 J = c_{Al}* 125 g * (-74.95ºC) (4)

       c_{Al} = \frac{-8,368J}{125g*(-74.95ºC} = 0.893 J/gºC (5)

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What mRNA sequence would result from the following DNA sequence?
Nezavi [6.7K]

Answer:

UAC CUG AGG AUC

Explanation:

<em>The mRNA sequence from ATG GAC TCC TAG DNA sequence would be </em><em>UAC CUG AGG AUC.</em>

<u>According to Chargaff's base pairing rule, the purine bases always pair with pyrimidine bases. Specifically, Adenine base must pair with Thymine base while Guanine base must pair with Cytosine base. In RNA, Thymine base is replaced with Uracil base.</u>

Hence:

ATG   GAC   TCC   TAG will pair with

UAC   CUG   AGG   AUC

5 0
3 years ago
We decided to make an iced latte by adding ice to a 200 mL hot latte at 45 °C. The ice starts out at 0 C. How much ice do we nee
tankabanditka [31]

Answer:

m = 77.75 g

Explanation:

Here we know that at equilibrium the temperature of the system will be 10 degree C

so heat given by hot latte = heat absorbed by the ice

now we have

heat given by latte = m s\Delta T

Q_1 = (200)(4.186)(45 - 10)

Q_1 = 29302 J

now heat absorbed by ice is given as

Q_2 = mL + ms\Delta T

Q_2 = m(335 + 4.186(10 - 0))

Q_2 = m(376.86)

now by heat balance we have

Q_1 = Q_2

29302 = m(376.86)

m = 77.75 g

6 0
2 years ago
Two identical light springs with spring constant k3 are now individually hung vertically from the ceiling and attached at each e
anyanavicka [17]

Answer:

 Keq = 2k₃

Explanation:

We can solve this exercise using Newton's second one

                F = m a

Where F is the eleatic force of the spring F = - k x

Since we have two springs, they are parallel or they are stretched the same distance by the object and the response force Fe is the same for the spring age due to having the same displacement

          F + F = m a

         k₃ x + k₃ x = m a

         a = 2k₃  x / m

To find the effective force constant, suppose we change this spring to what creates the cuddly displacement

       Keq = 2k₃

6 0
3 years ago
A 3200-lb car is moving at 64 ft/s down a 30-degree grade when it runs out of fuel. Find its velocity after that if friction exe
Karolina [17]

Answer:

The velocity is 40 ft/sec.

Explanation:

Given that,

Force = 3200 lb

Angle = 30°

Speed = 64 ft/s

The resistive force with magnitude proportional to the square of the speed,

F_{r}=kv^2

Where, k = 1 lb s²/ft²

We need to calculate the velocity

Using balance equation

F\sin\theta-F_{r}=m\dfrac{d^2v}{dt^2}

Put the value into the formula

3200\sin 30-kv^2=m\dfrac{d^2v}{dt^2}

Put the value of k

3200\times\dfrac{1}{2}-v^2=m\dfrac{d^2v}{dt^2}

1600-v^2=m\dfrac{d^2v}{dt^2}

At terminal velocity \dfrac{d^2v}{dt^2}=0

So, 1600-v^2=0

v=\sqrt{1600}

v=40\ ft/sec

Hence, The velocity is 40 ft/sec.

4 0
3 years ago
The work accomplished (produced) by a machine is called Work _____
Nonamiya [84]
I think it’s output because output work is work done by a machine
6 0
3 years ago
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