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dedylja [7]
2 years ago
13

The following is the longitudinal characteristic equation for an F-89 flying at 20,000 feet at Mach 0.638. The Short Period natu

ral frequency is _____.
Physics
1 answer:
BartSMP [9]2 years ago
8 0

Answer:

hello your question is incomplete  attached below is the missing part  

answer : short period oscillations frequency  = 0.063 rad / sec

              phugoid oscillations natural frequency ( w_{np} ) = 4.27 rad/sec

Explanation:

first we have to state the general form of the equation

= ( S^2 + 2\alpha _{p} w_{np} S + w^{2} _{np} ) (S^{2} + 2\alpha _{s} w_{ns}S + w^{2} _{ns}  ) = 0

where :

w_{np}  = Natural frequency of plugiod oscillation

\alpha _{p} = damping ratio of plugiod  oscilations

comparing the general form with the given equation

w^{2} _{np}  = 18.2329

w^{2} _{ns} = 0.003969

hence the short period oscillation frequency ( w_{ns} ) =  0.063 rad/sec

phugoid oscillations natural frequency ( w_{np} ) = 4.27 rad/sec

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3 years ago
You are given a vector in the xy plane that has a magnitude of 84.0 units and a y-component of -67.0 units.
melomori [17]

Answer:

Explanation:

a)Magnitude = \sqrt{(x1-y2)^{2}  + (x1-x2)^{2} }

84=\sqrt{(0- (-67))^{2}  + (x-0)^{2} }

x= +50.67 or -50.67 units

b) We are given that the resultant is entirely in the -ve x direction which means that the y-component of the resultant is 0; It means that the y-component of the next vector = -ve of the y component of the initial vector i.e 67.

To make the magnitude 80 units in the negative x direction where the y component is 0, the x component must be -130.67(-50.67 - 80) as the x component is + 50.67units.

Magnitude = \sqrt{(0- (67))^{2}  + (-130.67)^{2} } = 146.85 units

c) The direction vector = 67/146.85 i  - 130.67/146.85 j where i corresponds to the vector in y direction and j corresponds to the vector in x direction. Or this vector is at an angle of 180 - Tan^{-1}(67/130.67)degrees i.e 152.85 degrees from the +ve x-axis.

5 0
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a whistle you use to call your hunting dog has a frequency of 21 khz, but your dog is ignoring it. you suspect the whistle may n
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f = f_0 (\frac{v-v_0}{v})

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v_0 = Velocity of the observer

v = Velocity of the speed

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v = 340m/s \rightarrow \text{Speed of sound}

f = 20kHz \rightarrow \text{Apparent frequency}

f_0 = 21kHz \rightarrow \text{Original frequency}

Using the previous equation,

f = f_0 (\frac{v-v_0}{v})

Rearrange to find the velocity of the observer

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4 0
3 years ago
A small plane flies 37.0 km in a direction 45° north of east and then flies 28.0 km in a direction 25° north of east.
Karo-lina-s [1.5K]

Answer:

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In order to find the position of the plane after finishing the flight, we need to find its final coordinates (x₁, y₁).

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⇒ θ = 36.4º North of East (counterclockwise from the east axis).

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