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dedylja [7]
3 years ago
13

The following is the longitudinal characteristic equation for an F-89 flying at 20,000 feet at Mach 0.638. The Short Period natu

ral frequency is _____.
Physics
1 answer:
BartSMP [9]3 years ago
8 0

Answer:

hello your question is incomplete  attached below is the missing part  

answer : short period oscillations frequency  = 0.063 rad / sec

              phugoid oscillations natural frequency ( w_{np} ) = 4.27 rad/sec

Explanation:

first we have to state the general form of the equation

= ( S^2 + 2\alpha _{p} w_{np} S + w^{2} _{np} ) (S^{2} + 2\alpha _{s} w_{ns}S + w^{2} _{ns}  ) = 0

where :

w_{np}  = Natural frequency of plugiod oscillation

\alpha _{p} = damping ratio of plugiod  oscilations

comparing the general form with the given equation

w^{2} _{np}  = 18.2329

w^{2} _{ns} = 0.003969

hence the short period oscillation frequency ( w_{ns} ) =  0.063 rad/sec

phugoid oscillations natural frequency ( w_{np} ) = 4.27 rad/sec

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Eddi Din [679]
If a musician plays a wrong note, he will disrupt the harmony of rhythm of the song. This is because, he will be able to produce a sound of different wavelength which will cause a possible destructive interference with the waves being produced by his groupmates. 
8 0
3 years ago
11) Arthur and Betty start walking toward each other when they are 100 m apart. Arthur has a speed of 3.0 m/s and Betty has a sp
sleet_krkn [62]

Answer:

100 m

Explanation:

Arthur and Betty should be walking the same amount of time if they start walking at the same time and stop when they meet = t

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Speed of Betty = 2 m/s

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Distance covered by Arthur = 3t

Distance covered by Betty = 2t

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3t+2t=100\\\Rightarrow 5t=100\\\Rightarrow t=\frac{100}{5}\\\Rightarrow t=20\ s

The speed of dog is 5 m/s

Spot is running back and forth at 5 m/s for 20 seconds

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\mathbf{5\times 20}=\mathbf{100\ m}

5 0
4 years ago
A small grinding wheel has a moment of inertia of 4.0*10-5kgm2. What net torque must be applied to the wheel for its angular acc
kvv77 [185]

Hi there!

We can use the rotational equivalent of Newton's Second Law:

\huge\boxed{\Sigma \tau = I \alpha}

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α = Angular acceleration (rad/sec²)

We can plug in the given values to solve.

\Sigma \tau = (4 * 10^{-5})(150) = \boxed{0.006 Nm}

4 0
3 years ago
if charge is located at center of spherical volume and electric flux through surface of sphere is Φ what would be flux through s
jonny [76]

Answer:

The flux will be nine times as great.

Explanation:

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\Phi_E=\int\limits {Ecos\theta dS} \,

The electric field (E) is parallel to the surface vector (dS), so \theta=0

\Phi_E=\int\limits{Ecos(0)dS} \,\\\Phi_E=E\int\limits{dS} \,\\\Phi_E=ES\\\Phi_E=E4\pi r^2

Since the electric flux is proportional to the square of the sphere's radius,  if radius of sphere were tripled, the flux will be nine times as great.

7 0
3 years ago
The lens in the eyepiece of a reflecting telescope breaks. How will this most affect the function of the telescope?
Serggg [28]

Answer:

B

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Explanation:

I did it and this was the correct answer

5 0
3 years ago
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