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madam [21]
3 years ago
7

What is the string theory.

Physics
2 answers:
Leno4ka [110]3 years ago
7 0
String the·o·ry
noun
a cosmological theory based on the existence of cosmic strings.
andrezito [222]3 years ago
4 0

In physics, string theory is a theoretical framework in which the point-like particles of particle physics are replaced by one-dimensional objects called strings. It describes how these strings propagate through space and interact with each other.

Hope this helps! :-)

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Answer:

Haha pretty funny

Explanation:

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A student is running to catch the campus shuttle bus, which is stopped at the bus stop. The student is runnign at a constant spe
Serggg [28]

Answer:

Part a)

t = 16.8 s

d = 100.8 m

Part b)

v_f = 2.86 m/s

Explanation:

Part a)

Constant speed by which the student will run is given as

v = 5 m/s

now after some time if student is going to overtake the position of bus

so here the final positions will be same

so we have

x_{bus} = x_{student}

0 + \frac{1}{2}at^2 + d = v_{student} t

\frac{1}{2}(0.170)t^2 + 60 = 5 t

0.085 t^2 - 5t + 60 = 0

so it is

t = 16.8 s

So student will run the total distance

d = vt

d = (6)(16.8)

d = 100.8 m

Part b)

Speed of bus when student reach the bus is given as

v_f = v_i + at

v_f = 0 + (0.170)(16.8)

v_f = 2.86 m/s

4 0
4 years ago
A baseball is batted. It's a long fly ball. 4 seconds later the ball reaches the outfield 100 meters away and returns to the hei
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Answer:

25 m/s

Explanation:

First we should define the variables

T=4

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We can use formula 1 from the BIG 5

x=(v+v0)t/2

By plugging in our variables we can get 100=4(v+v0)/2

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3 years ago
IF YOU MOVE 50 METERS IN TO SECONDS,
Yanka [14]
You can use photo math for This
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A car is moving in the positive direction along a straight highway and accelerates at a constant rate while going from point A t
rusak2 [61]

Answer:

The time where the avergae speed equals the instaneous speed is T/2

Explanation:

The velocity of the car is:

v(t) = v0 + at

Where v0 is the initial speed and a is the constant acceleration.

Let's find the average speed. This is given integrating the velocity from 0 to T and dividing by T:

v_{ave} = \frac{1}{T}\int\limits^T_0 {v(t)} \, dt

v_ave = v0+a(T/2)

We can esaily note that when <u><em>t=T/2</em></u><u><em> </em></u>

v(T/2)=v_ave

Now we want to know where the car should be, the osition of the car is:

x(t) = x_A + v_0 t + \frac{1}{2}at^2

Where x_A is the position of point A. Therefore, the car will be at:

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