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4 years ago

A substance that is present in a solution in a smaller amount and is dissolved by the solvent is called the solute.

Physics

1 answer:

Hunter-Best [27]4 years ago

4 0

<span>a solution is a liquid mixture </span>

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A pipe is horizontal and carries oil that has a viscosity of 0.14 Pa s. The volume flow rate of the oil is 5.3 × 10-5 m3/s. The

Liula [17]

Answer:

Explanation:

Given

$\mu =0.14 Pa.s$

Volume Flow rate $Q=5.3\times 10^{-5} m^3/s$

Length $L=37 m$

radius $r=0.58 cm$

$D=1.16 cm$

According to Hagen-Poiseuille Equation

difference in Pressure is given

$\Delta P=\frac{128\mu L\cdot Q}{\pi D^4}$

$P_{in}-P_{out}=\frac{128\mu L\cdot Q}{\pi D^4}$

$P_{in}=P_{out}+\frac{128\mu L\cdot Q}{\pi D^4}$

$P_{in}=1.01325\times 10^5+\frac{128\times 0.14\times 37\times 5.3\times 10^{-5}}{\pi\cdot 1.16^4\times 10^{-8}}$

$P_{in}=1.01325\times 10^5+6.17\times 10^5$

$P_{in}=7.19\times 10^5$

3 0

3 years ago

Imagine that someone is sitting down to enjoy a cup of coffee or hot chocolate. Use your experiences to describe how heat flows

Reika [66]

The heat flows into my body and I start with a warming feeling going down my throat as it starts there I get this warm feeling and I break out in a coldsweat from consuming a warm drink a cold drink will help cool me down :

Explanation:

If drink warm will make u warm drinking cool will make u cool down faster

8 0

3 years ago

Read 2 more answers

Pushing a rock from a hill top is called

wariber [46]

It's called "utter disregard for the safety and welfare
of the people standing at the bottom of the hill".

6 0

3 years ago

A mountain climber weighs 42.0 N. If he climbs a hill 100m high. Calculate the work done in joules

quester [9]

Answer:

The answer is 4200 J.

Explanation:

The formula of work done is, W = F×D where F is the force of an object and D is the distance. Then you just substitute the values into the equation :

W = F×D

F = 42N

D = 100m

W = 42 × 100

= 4200 J

5 0

3 years ago

A 15-lb block B starts from rest and slides on the 25-lb wedge A, which is supported by a horizontal surface. Neglecting frictio

xxTIMURxx [149]

The angle of the wedge is 30°.

Answer:

5.88 ft/s

Explanation:

a) The block will slide down due to it's weight.

initial velocity u= 0

final velocity, v

acceleration, a = g sin 30° = 32 ft/s²× sin 30° = 16 ft/s²

Sliding displacement, s = 3ft

Use third equation of motion:

$v^2-u^2 = 2as$

substitute the values and solve for v

$v^2-0 = 2\times 16 \times 3 =96 ft^2/s^2\\v = 9.8 ft/s$

b) Use conservation of momentum:

Initial momentum of the system = 0

final momentum = (15) ( 9.8)+ (25)(v')

v' = 5.88 ft/s

3 0

3 years ago