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SpyIntel [72]
3 years ago
9

A 1400 kg car is moving at 12 m/s when the driver stops a car what increase in the thermal energy of the car and it surroundings

results from a find the brakes to bring the car to a stop
Physics
2 answers:
butalik [34]3 years ago
5 0
KE = 1/2 mv^2

in this case, the initial kinetic energy which is converted to heat is 

KE = 1/2 1400 (12)^2

KE = 100,800 J
seropon [69]3 years ago
3 0

KE = 1/2 1400 (12)^2

KE = 100,800 J

Answer: 1.0 x 10^5 J


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Lelechka [254]

The two possible angles obtained by using the qudratic equation are;

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For the motion along x direction, time period can be calculated as follows:

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35 = (50 × cosθ) t

t = 0.64 / cosθ

For the motion in y direction, an equation can be obtained as follows:

s_{y} = (v_{A})_{y}  t +\frac{1}{2} (a_{y} )t^{2}

s_{y} = (-v_{A}sinθ) }  t +\frac{1}{2} (a_{y} )t^{2}

Plugging in the values we get:

-20 = (-50_sinθ) }  t +\frac{1}{2} (-32.2} )t^{2}

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Upon solving the above quadratic equation, we get,

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tanθ_{1} = 0.27

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and, tanθ_{2} = -3.38

θ_{2} = 73.51

Learn more about quadratic equation here:

brainly.com/question/17177510

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