Answer:
There is a 2/3 probability that the other side is also black.
Step-by-step explanation:
Here let B1: Event of picking a card that has a black side
B2: Event of picking a card that has BOTH black side.
Now, by the CONDITIONAL PROBABILITY:
Now, as EXACTLY ONE CARD has both sides BLACK in three cards.
⇒ P (B1 ∩ B2) = 1 /3
Also, Out if total 6 sides of cards, 3 are BLACK from one side.
⇒ P (B1 ) = 3 /6 = 1/2
Putting these values in the formula, we get:
⇒ P (B2 / B1) = 2/3
Hence, there is a 2/3 probability that the other side is also black.
Answer: (-∞, 0)The graph of the parent absolute value function is decreasing over the interval (–∞, 0)
The graph drawn for the absolute value parent function is usually made up of two linear "pieces" which meet at a common vertex (the origin; 0, 0). The graph is symmetric around the y axis and generally takes a V shape or an inverted V shape. The absolute/relative minimum of the graph is 0 but there it has no absolute maximum; so the absolute maximum is usually represented by ‘∞’ (infinitive). Typically, the graph of the parent absolute value function is increasing over the interval (0, ∞), and is decreasing over the interval (-∞, 0).
Answer:
x = −4
Step-by-step explanation:
Add x to both sides of the equation. x + 4 + x = − 4 Add x and x . 2 x + 4 = −4
Subtract 4 from both sides of the equation. 2 x = −4 − 4 Subtract 4 from - 4. 2x = −8
Divide each term in 2x = −8 by 2. 2x/2 = −8/2
Cancel the common factor. 2x/ 2 = −8/2 Divide x by 1. x = −8/2
Divide −8 by 2. x = −4
x = 0
This is because 4 x 0 = 0 and 3 x 0 = 0. That leaves us with 5, and 5 = 5. Therefore x = 0
