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4 years ago

(4-10+2)^3 ? simplify the expression

Mathematics

1 answer:

NNADVOKAT [17]4 years ago

7 0

Im using pemdas so the parentheses go first, 4-10+2 is -4 and if you cube that (exponents) then it would be -64

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6h^5+0h^4-12h^3+0h^3+0h=0

aliya0001 [1]

<h2>The value of h = 0, ± $\sqrt{2}$ </h2>

Step-by-step explanation:

We have,

$6h^5+0h^4-12h^3+0h^3+0h=0$

To find, the value of h = ?

∴ $6h^5+0h^4-12h^3+0h^3+0h=0$

⇒ $6h^5$ + (0) $h^4$ - 12 $h^3$ + (0) $h^3$ + (0)h = 0

⇒ $6h^5$ + 0 - 12 $h^3$ + 0 + 0 = 0

⇒ $6h^5$ - 12 $h^3$ = 0

Taking 6 $h^3$ as common, we get

$6h^3(h^2-2)$ = 0

⇒6 $h^3$ = 0 or, $h^2$ - 2 = 0

⇒ 6 $h^3$ = 0 ⇒ h = 0

⇒ $h^2$ = 2

⇒ h = ± $\sqrt{2}$

Hence, the value of h = 0, ± $\sqrt{2}$

7 0

4 years ago

One pound of candies costs $3.50. How much will we have to pay for 3 lb?

Romashka-Z-Leto [24]

Answer: 10.50 dollars

Step-by-step explanation:

3.50 x 3 = 10.50

8 0

3 years ago

Suppose a publishing company estimates that its monthly cost is C(x) = 600{x^2} + 300xC(x)=600x 2 +300x and its monthly revenue

Leto [7]

Answer:

the answer is A,

P(x) = -0.4x³+100x²-900x+500

Step-by-step explanation:

monthly cost:

$c(x) = 600x {}^{2} + 300x$

monthly revenue:

$r(x) = - 0.4 {}^{3} + 700x {}^{2} - 600x + 500$

profit function:

$p(x) = r(x) - c(x)$

$p(x) = ( - 0.4x {}^{3} + 700 {x}^{2} - 600x + 500) - (600x {}^{2} + 300x)$

i) remove the first bracket

$p(x) = - 0.4x {}^{3} + 700x {}^{2} - 600x + 500 - (600 {x}^{2} + 300x)$

ii) there is a negative sign, '-' in front of the second bracket. so, change the sign of each term of the expression inside the bracket

$p(x) = - 0.4x {}^{3} + 700 {x}^{2} - 600x + 500 - 600x {}^{2} - 300x$

iii) collect like terms

$p(x) = - 0.4x {}^{3} + 700 {x}^{2} - 600 {x}^{2} - 600x - 300x + 500$

iv) simply the like terms

$p(x) = - 0. 4{x}^{3} + 100 {x}^{2} - 900x + 500$

6 0

3 years ago

A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi

SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

$= \frac{20!}{(20-5)! 5!)}$