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babunello [35]
4 years ago
6

(4-10+2)^3 ? simplify the expression

Mathematics
1 answer:
NNADVOKAT [17]4 years ago
7 0
Im using pemdas so the parentheses go first, 4-10+2 is -4 and if you cube that (exponents) then it would be -64
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A wire is attached at the top of a 500 ft vertical antenna and is staked in the ground 1200 ft from the base of the antenna. how
Pie
A^2 + b^2 = c^2
(500)^2 + (1200)^2 = c^2
1,690,000 = c^2
take the square root of 1,690,000
Answer is 1,300 feet
4 0
3 years ago
Increase 14187.13 by 14.5
katrin2010 [14]

Answer:

14201.63

Step-by-step explanation:

14187.63

+   14.50

=14201.63

7 0
3 years ago
How to do frackions , percents, and how to convert frackions.
Vera_Pavlovna [14]

Answer:

To convert a decimal to percent, we multiply the decimal by 100. To convert a fraction to decimal, we divide the numerator by the denominator using long division and to convert a fraction to percent, we convert the fraction to decimal and the decimal to percent.

6 0
3 years ago
HELP WILL MARK YOU BRAINLIEST HURRY IM ON A TIME LIMIT!’
Keith_Richards [23]

(3x+5)+(x+3)=180

4x+8=180

4x=172

x=43

3(43)+5

<PQR=134

<SQR=46

6 0
3 years ago
Read 2 more answers
La probabilidad de que el estudiante A apruebe un examen de MM-100 es 0.6, la probabilidad de que apruebe un estudiante B es 0.4
ivanzaharov [21]

Answer:

0.5 = 50% probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.

Step-by-step explanation:

La probabilidad condicional :

P(B|A) = \frac{P(A \cap B)}{P(A)}

En el cual:

P(B|A) es la probabilidad de que ocurra el evento B, dado que A sucedió.  

P(A \cap B) es la probabilidad de que ocurran tanto A como B.  

P(A) es la probabilidad de que ocurra A.

En esta pregunta :

Evento A: Estudiante A aprueba.

Evento B: Estudiante B aprueba.

La probabilidad de que el estudiante A apruebe un examen de MM-100 es 0.6

Entonces P(A) = 0.6

La probabilidad de que ambos estudiantes aprueben es 0.3

Entonces P(A \cap B) = 0.3

¿Cual es la probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3}{0.6} = 0.5

0.5 = 50% probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.

6 0
3 years ago
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