The answer is surface waves
Answer:
B) exposure to red light
Explanation:
Plants use a phytochrome system to sense the level, intensity, duration, and color of environmental light do as to adjust their physiology.
The phytochromes are a family of chromoproteins with a linear tetrapyrrole chromophore, similar to the chlorophyll. Phytochromes have two photo-interconvertible forms: Pr and Pfr. Pr absorbs red light (~667 nm) and is immediately converted to Pfr. Pfr absorbs far-red light (~730 nm) and is quickly converted back to Pr. Absorption of red or far-red light causes a massive change to the shape of the chromophore, altering the conformation and activity of the phytochrome protein to which it is bound. Together, the two forms represent the phytochrome system.
Answer:
3040 torr
Explanation:
Applying,
PV = P'V'..................... Equation 1
Where P = Initial Pressure, V = Initial volume, P' = Final pressure, V' = Final volume.
Make P' the subject of the equation
P' = PV/V'................. Equation 2
From the question,
Given: P = 760 torr, V = 56.2 L, V' = 56.2/4 = 14.05 L
Substitute these values into equation 2
P' = (56.2×760)/14.05
P' = 3040 torr
Answer:
For C1, Q = 1.6125×10⁻³ C
For C2, Q = 6.25×10⁻⁴ C
Explanation:
Note: Since the capacitors are connected in parallel, The voltage across each of them is equal.
From the question,
Q = CV........................ Equation 1
Where Q = Charge on the capacitor, V = Voltage across the capacitor, C = Capacitance of the capacitor.
For the first capacitor,
Q = C1V............. Equation 2
Where C1 = 6.45 μF= 6.45×10⁻⁶ F, V = 250 V
Substitute into equation 2
Q = (6.45×10⁻⁶ )(250)
Q = 1.6125×10⁻³ C.
For the the second capacitor,
Q = C2V............. Equation 3
Given: C2 = 2.50 μF = 2.5×10⁻⁶ F, V = 250 V
Q = (2.5×10⁻⁶ )(250)
Q = 6.25×10⁻⁴ C
What you’re doing is so easy pay attention more I think
