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2 years ago

Help me write this three paragraph Physics essay. I'll Venmo you, give me asking price.

Physics

1 answer:

viktelen [127]2 years ago

8 0

Answer:

Physics, or the study of matter, energy, and the interactions between them, helps us to understand the laws and rules that govern the physical world. Not every student will grow up and study physics on a deeper level, but everyone uses basic physics concepts to navigate everyday life.A

Physics is a natural science that involves the study of matter and its motion through space and time, along with related concepts such as energy and force. More broadly, it is the study of nature in an attempt to understand how the universe behaves.Physics helps you to understand the world around you, and satisfy your curiosity. Studying physics develops your critical thinking and problem-solving skills. Physicists are versatile, which opens a wide range of future careers.

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Running at maximum speed, it takes a boat times as long to go 10 miles upstream as it does to go 10 miles downstream. If the cur

Greeley [361]

Note: <em>The question states the time to go upstream is a number of times (not explicitly written) the time to go downstream. We'll assume a general number N</em>

Answer:

$\displaystyle v_b=\frac{N+1}{N-1}(4\ mph)$

Explanation:

<u>Relative Speed</u>

If a boat is going upstream against the water current, the true speed of motion is $v_b-v_w$ , being $v_b$ the speed of the boat and $v_w$ the speed of the water. If the boat is going downstream, the true speed becomes $v_b+v_w$ .

The question states the time to go upstream is a number of times N (not explicitly written) the time to go downstream. The speed of an object is computed as

$\displaystyle v=\frac{x}{t}$

Where x is the distance traveled and t the time taken for that. The time can be computed by

$\displaystyle t=\frac{x}{v}$

If $t_u$ is the time for the upstream travel and $t_d$ is the time for the downstream travel, then

$t_u=Nt_d$

Siince the same distance x= 10 miles is traveled in both cases:

$\displaystyle \frac{10}{v_b-v_w}=N\frac{10}{v_b+v_w}$

Simplifying and rearrangling

$v_b+v_w=N(v_b-v_w)$

Operating

$v_b+v_w=Nv_b-Nv_w$

Solving for $v_b$

$\displaystyle v_b=\frac{N+1}{N-1}v_w$

$If\ N=2,\ v_w=4\ mph$

$\displaystyle v_b=\frac{3}{1}(4)=12\ mph$

If N=3

$\displaystyle v_b=\frac{4}{2}v_w=2(4)=8\ mph$

We can use the required value of N to compute the speed of the boat as explained

7 0

4 years ago

What is the term for the ability to cause change in matter?

Leokris [45]

Answer:

A. Energy

Explanation:

You can change energy from one form to another when you lift your arm or take a step. Energy is used to move matter. In this scenario, the matter would be you.

3 0

3 years ago

How much work does the electric field do in moving a proton from a point with a potential of +145 v to a point where it is -55 v

Aleks04 [339]

The work done by the electric field in moving a charge is the negative of the potential energy difference between the two locations, which is the product between the magnitude of the charge q and the potential difference $\Delta V$ :
$W=-\Delta U=-q\Delta V=-q (V_f -V_i)$
The proton charge is $q=1.6 \cdot 10^{-19}C$ , and the two locations have potential of $V_i = +145 V$ and $V_f=-55 V$ , therefore the work is
$W=-(1.6 \cdot 10^{-19}C)(-55 V-(+145 V))=3.2 \cdot 10^{-17}J$

5 0

3 years ago

Which variable would be most useful in determining the number of people eligible for retirement benefits in a certain year?

KonstantinChe [14]

The answer is

D. Age structure

8 0

3 years ago

A resistor with an unknown resistance is connected in parallel to a 13 Ω resistor. When both resistors are connected in parallel

larisa86 [58]

Answer:

R2 = 10.31Ω

Explanation:

For two resistors in parallel you have that the equivalent resistance is:

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\\$ (1)

R1 = 13 Ω

R2 = ?

The equivalent resistance of the circuit can also be calculated by using the Ohm's law:

$I=\frac{V}{R_{eq}}\\\\R_{eq}=\frac{V}{I}$ (2)

V: emf source voltage = 23 V

I: current = 4 A

You calculate the Req by using the equation (2):

$R_{eq}=\frac{23V}{4A}=5.75\Omega$

Now, you can calculate the unknown resistor R2 by using the equation (1):

$\frac{1}{R_2}=\frac{1}{R_{eq}}-\frac{1}{R_1}\\\\R_2=\frac{R_{eq}R_1}{R_1-R_{eq}}\\\\R_2=\frac{(5.75\Omega)(13\Omega)}{13\Omega-5.75\Omega}=10.31\Omega$

hence, the resistance of the unknown resistor is 10.31Ω

8 0

3 years ago

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