Answer:
AAS SAS LL LA Hope this helps :)
Step-by-step explanation:
a) AAS b) SAS d) LL f) LA
Given is a diagram containing two right triangles.
ABC, DEF are the triangles
Given that
AB=DE
AC=DF
Angle A = Angle D (right angle)
Angle B = Angle E
Hence we have for two sides, one angle so ASA
Or two legs and containing angle hence SAS
Also right triangle, one acute and one leg so LA axiom
Besides, two legs equal in right triangle, so LL axiom
23
Good Luck!!!
use a calculator du bro 56
x = -13,67
-3x - 5 = 36
-3x = 36 + 5
-3x = 41
x = 41/-3
x = -13 2/3
or
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