Answer:
v=30 m/s
Explanation:
h - height
g - acceleration due to gravity=10
t - time
v- velocity

45 = 5t²
t² = 9
t=3 seconds
v=g×t
v=10×3
v=30 m/s
To solve this problem it is necessary to apply the concepts related to the continuity of fluids in a pipeline and apply Bernoulli's balance on the given speeds.
Our values are given as


From the continuity equations in pipes we have to

Where,
= Cross sectional Area at each section
= Flow Velocity at each section
Then replacing we have,



From Bernoulli equation we have that the change in the pressure is

![7.3*10^3 = \frac{1}{2} (1000)([ \frac{(1.25*10^{-2})^2 }{0.6*10^{-2})^2} v_1 ]^2-v_1^2)](https://tex.z-dn.net/?f=7.3%2A10%5E3%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%281000%29%28%5B%20%5Cfrac%7B%281.25%2A10%5E%7B-2%7D%29%5E2%20%7D%7B0.6%2A10%5E%7B-2%7D%29%5E2%7D%20v_1%20%5D%5E2-v_1%5E2%29)


Therefore the speed of flow in the first tube is 0.9m/s
Answer:
4/3 pi R^3 = pi r^2 L equating volume of sphere and wire
r = (4 R^3 / 3 * L)^1/2 solving for radius of wire
r = (4 * 6^3 / 3 * 32)^1/2
r = 9^1/2 cm = 3 cm = .03 meters
108 681(nearest whole day)
Complete Question
Use Stefan's law to find the intensity of the cosmic background radiation emitted by the fireball of the Big Bang at a temperature of 2.81 K. Remember that Stefan's Law gives the Power (Watts) and Intensity is Power per unit Area (W/m2).
Answer:
The intensity is
Explanation:
From the question we are told that
The temperature is 
Now According to Stefan's law

Where
is the Stefan Boltzmann constant with value 
Now the intensity of the cosmic background radiation emitted according to the unit from the question is mathematically evaluated as

=> 
=> 
substituting values

