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Brut [27]
3 years ago
7

Does the moon fall partly into earth's shadow when it is n "full"?

Physics
1 answer:
murzikaleks [220]3 years ago
5 0
Yes, <span> the moon fall partly into earth's shadow when it is in its full size</span>
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I need help with number 6
Otrada [13]
I like your handwriting boy
7 0
3 years ago
two porters are available to carry a long timber wood.out of them one is weak.how to do you make less load to the weak one? writ
marshall27 [118]

Answer:

Please find the answer in the explanation.

Explanation:

Given that two porters are available to carry a long timber wood.out of them one is weak. how do you make less load to the weak one?

We can make the weak one to carry less load through two different ways or means.

First, if we can locate the centre of gravity and centre of mass of the long timbre wood, the week one can carry the other end away from the center of gravity and centre of mass.

Second, the strong porter can carry the long timbre wood almost to the fulcrum and allow the weak one to support at the other end. By doing this, the weak one will only carry light portion of the load.

4 0
3 years ago
How does friction affect the distance of an object?
stiv31 [10]
It slows the object down so it cannot move well and evetually the object cannot be pushed and farther
4 0
3 years ago
A sample has a density of 30 g/ml. there is 60 ml of this substance.how much does it weigh?
aleksandrvk [35]
If each mL has 30 grams of the substance in it, then 60 mL have 1800 grams of mass in them. the weight of 1,800 grams of mass on Earth is (1.8 kg) x (9.8 m/s^2) = 17.6 newtons.
3 0
3 years ago
A 50-cm-long spring is suspended from the ceiling. A 270 g mass is connected to the end and held at rest with the spring unstret
I am Lyosha [343]

Answer:

The spring constant is 45.94 N/m.

Explanation:

Given that,

Length = 50 cm

Mass = 270 g

Stretching the spring = 24 cm

We need to calculate the spring constant

Using formula of energy

The change in potential energy equal to the change in kinetic energy.

mgh=\dfrac{1}{2}kx^2

Put the value into the formula

270\times10^{-3}\times9.8\times50\times10^{-2}=\dfrac{1}{2}\times k\times(24\times10^{-2})^2

k=\dfrac{2\times270\times10^{-3}\times9.8\times50\times10^{-2}}{(24\times10^{-2})^2}

k=45.94\ N/m

Hence, The spring constant is 45.94 N/m.

3 0
3 years ago
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