Answer:
A) q = -8.488 cm , B) m = 0.29
Explanation:
A) For this exercise in geometric optics, we will use the equation of the constructor
where p and q are the distance to the object and image, respectively and f is the focal length
in our case the distance the object is p = 29 cm the focal length of a diverging lens is negative and indicates that it is f = - 12 cm
we calculate
= - 0.1178
q = -8.488 cm
the negative sign indicates that the image is virtual
B) the magnification is given
we substitute
m =
m = 0.29
the positive sign indicates that the image is right