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sdas [7]
3 years ago
11

PLEASE HELP ASAP! URGENT!

Mathematics
2 answers:
prohojiy [21]3 years ago
5 0
What’s the question?
algol [13]3 years ago
3 0
You didn’t post the question
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an angles measure is 6 degrees more than 3 times the measure of its complwment. find the measure of the angles.
irina1246 [14]

Answer:

The angles are 22.5 and 67.5.

Step-by-step explanation:

A complement is the angle that when added to the given angle gives 90 degrees.

Therefore, the angle x is 3 times larger than its complement.

This means that x is 3/4 of 90 degrees and complement is 1/4 of 90 degrees.

Therefore, the angles are 22.5 and 67.5.

3 0
3 years ago
Simplify 9 to the 2nd over 9 to the 7th.
Free_Kalibri [48]

9^2/9^7

when dividing powers, we subtract the exponents

9^(2-7)

9^ (-5)

a negative exponent flips from the numerator to the denominator

1/ 9^5

Choice D

6 0
3 years ago
Read 2 more answers
Find the vertex of the function h(x) = x2 – 4x – 21
lakkis [162]

Answer: (2, -25)

Step-by-step explanation:

The x coordinate of the vertex is x=-\frac{-4}{2(1)}=2.

When x=2, h(2)=2^2 - 4(2)-21=-25.

So, the vertex is (2, -25).

7 0
2 years ago
Drag the expressions into the boxes to correctly complete the table.
lora16 [44]

Answer:

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form ax^n.

Here:

n = non-negative integer

a = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

x^4+\frac{5}{x^3}-\sqrt{x}+8

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains \sqrt{x}, so it is not a polynomial.

Also it contains the term \frac{5}{x^3} which can be written as 5x^{-3}, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression x^4+\frac{5}{x^3}-\sqrt{x}+8 is not a polynomial.

Given the expression

-x^5+7x-\frac{1}{2}x^2+9

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

\left|x\right|^2+4\sqrt{x}-2

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

x^3-4x-3

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

\frac{4}{x^2-4x+3}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

3 0
3 years ago
A cylinder has a volume of 321 cubic units. If a cone has the same height and radius as the cylinder, what is the volume in cubi
Sati [7]
Cone's volume is third of cylinder's volume, so 321*1/3=107 cubic units. Answer A. is correct.
4 0
3 years ago
Read 2 more answers
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